无法从Play框架发送电子邮件

时间:2013-09-26 07:29:21

标签: java playframework javamail playframework-2.2

我正在尝试使用Play Framework发送电子邮件。在applications.conf中,当我设置smtp.mock = true时,它运行得非常好:

[info] application - HTML: Welcome to Play20StartApp. <br> Click on this link : http://localhost:9000/confirm/d77ea256-0d2e-4df5-b66e-e034159f8042 to confirm your email.<br><br>--<br>null
[debug] application - Mail sent - SMTP:smtp.google.com:465 SSL:yes user:username@gmail.com password:password

然而,当我评论smtp.mock = true并尝试发送真实的电子邮件时,我收到此错误:

[debug] application - Mail.sendMail: Mail will be sent to user1@gmail.com
[ERROR] [09/26/2013 03:46:05.014] [application-akka.actor.default-dispatcher-2] [TaskInvocation] From address required
org.apache.commons.mail.EmailException: From address required

我已将smtp.user设置为正确的值,即server@businessdomain.com。知道是什么导致了这个错误吗?

故障排除步骤

  1. 使用的电子邮件是真实的电子邮件,为了发布,它们是匿名的。同样,使用真实的域名
  2. 使用有效的本地邮件服务器(exim)进行测试,以及直接通过Gmail(smtp.google.com)和Google Apps(aspmx.l.google.com)服务器发送邮件。已使用邮件客户端验证这些设置。
  3. 下面的Java代码段完美无缺,

    import java.util。;     import javax.mail。;     import javax.mail.internet。;     import javax.activation。;

    public class SendEmail
    {
        public static void main(String [] args)
        {
            String to = "recipient@mydomain.com";
            String from = "sender@mydomain.com";
            String host = "localhost";
    
            Properties properties = System.getProperties();
    
            // Setup mail server
            properties.setProperty("mail.smtp.host", host);
    
            // Get the default Session object.
            Session session = Session.getDefaultInstance(properties);
    
            try{
                MimeMessage message = new MimeMessage(session);
    
                // Set From: header field of the header.
                message.setFrom(new InternetAddress(from));
    
                message.addRecipient(Message.RecipientType.TO,
                        new InternetAddress(to));
                message.setSubject("Subject of email");
                message.setText("This is actual message");
    
                Transport.send(message);
                System.out.println("Sent message successfully....");
            }catch (MessagingException mex) {
                mex.printStackTrace();
            }
        }
    }
    

1 个答案:

答案 0 :(得分:0)

如果您将邮件程序操作包装在Future(或Play Java等效文件)中,那么它可能是您遇到的变量范围问题:

这有效:

val mail = use[MailerPlugin].email
val async: Future[Unit] = Future{
  mail.setSubject(subject)
  mail.setRecipient(recipient)
  mail.setFrom(from)
  mail.send(body)
}
async.onFailure{case(e)=>
  Logger.error(s"mailer failed for $recipient due to: ${e.getMessage}")
}

工作:

val mail = use[MailerPlugin].email
mail.setSubject(subject)
mail.setRecipient(recipient)
mail.setFrom(from)
val async: Future[Unit] = Future{mail.send(body)}
async.onFailure{case(e)=>
  Logger.error(s"mailer failed for $recipient due to: ${e.getMessage}")
}

我假设封闭范围在Future封闭中可用;在这种情况下,绝对不会因为基础Apache Commons邮件程序保释“需要发件人地址”。果然,设置smtp.mock = true表明当mail.setFrom和friends填充在Future {...}范围之外时,fromAddress为null。

有趣的是,即使我将async val分解为本地方法并传入构造的邮件和正文:

private def async(mail: MailerAPI, body: String): Future[Unit] = Future{
  mail.send(body)
}

尽管直接传递了一个构建的邮件程序,但在Future之外设置的邮件属性仍然会结束 - 令人惊讶,不是吗?