我在csv文件中导出查询结果。代码如下所示:
$query = "SELECT DATE(punchdetails.punchin) as punchday,punchdetails.punchin,punchdetails.punchout,employeedetails.employeename
FROM punchdetails join(employeedetails) ON punchdetails.employeeid=employeedetails.employeeid
AND punchdetails.employeeid=$employeeid AND DATE(punchdetails.punchin)=$fromdate";
header("Content-type: application/csv");
header("Content-Disposition: attachment; filename=file.csv");
header("Pragma: no-cache");
header("Expires: 0");
ini_set('display_errors',1);
$private=1;
error_reporting(E_ALL ^ E_NOTICE);
$select_c = mysql_query($query);
while ($row = mysql_fetch_array($select_c))
{
$intime = strtotime($row['punchin']);
$mysqlintime = date( 'H:i:a', $intime );
$outtime = strtotime($row['punchout']);
$mysqlouttime = date( 'H:i:a', $outtime );
$result.=$row['employeename'].','.$row['punchday'].','.$mysqlintime.','.$mysqlouttime;
$result.="\n";
echo $result;
}
当我执行查询时,它正确地返回记录。但是当我将查询结果下载为csv文件时,记录会重复出现。我得到了生成的csv文件数据,如下所示:
Sonu,2013-09-26,10:55:am,11:12:am
Sonu,2013-09-26,10:55:am,11:12:am
Kristo,2013-09-26,11:23:am,11:24:am
我没有得到什么问题。任何人都可以帮我解决这个问题吗?提前谢谢。
答案 0 :(得分:1)
我看到了问题
你将每行result
连接起来,然后回声。因此,每次回显时 - 您将回显所有先前的结果+当前结果。
要么改变:
$result.=$row['employeename'].','.$row['punchday'].','.$mysqlintime.','.$mysqlouttime;
$result.="\n";
为:
echo $row['employeename'].','.$row['punchday'].','.$mysqlintime.','.$mysqlouttime;
echo "\n";
或将echo $result;
移到while循环之外
答案 1 :(得分:1)
你需要在while循环之外回显$ result:
$result='';
while ($row = mysql_fetch_array($select_c))
{
$intime = strtotime($row['punchin']);
$mysqlintime = date( 'H:i:a', $intime );
$outtime = strtotime($row['punchout']);
$mysqlouttime = date( 'H:i:a', $outtime );
$result.=$row['employeename'].','.$row['punchday'].','.$mysqlintime.','.$mysqlouttime;
$result.="\n";
}
echo $result;