Question

我一直在挖掘金字塔，我正在寻找设置中间件来服务我的api。我用werkzeug使用DispatchMiddleware完成了这个。

如何在金字塔中实现这一目标

project
 | __init__.py
 | api
 | | __init__.py
 | web
 | | __init__.py

项目/ API /的初始化的.py

def main(global_config, **settings):
    """ This function returns a Pyramid WSGI application.
    """
    config = Configurator(settings=settings)

    config.include('cornice')
    api_includes(config)
    config.scan() // scan only api_includes/routes

    app = config.make_wsgi_app()

    return app

项目/网络/的初始化的.py

def web_includes(config):
    config.include('project.posts', route_prefix='/post')

def main(global_config, **settings):
     """ This function returns a Pyramid WSGI application.
     """
     config = Configurator(settings=settings)
     config.include('pyramid_chameleon')
     config.add_static_view('static', 'static', cache_max_age=3600)

     web_includes(config)
     config.add_route('home', '/')
     config.scan() // only web_includes/routes
     app = config.make_wsgi_app()

     return app

项目/的初始化的.py

from pyramid.config import Configurator

from api import main as api_main
from web import main as web_main

from pyramid.wsgi import wsgiapp, wsgiapp2


def main(global_configs, **settings):
    web = wsgiapp2(web_main(global_configs, **settings))
    api = wsgiapp2(api_main(global_configs, **settings))


    config = Configurator()
    config.add_view(web, name='/')
    config.add_view(api, name='api')


    return config.make_wsgi_app()

在评价我的api时，它可以正常工作，但是除非我指定一个不是'/'或''的名称，否则它将无法使用网络路由：

config.add_view(web, name='foo')

转到/ foo或/ foo / post works

Answer 1

config.add_route('api', '/api/*subpath')
config.add_route('default', '/*subpath')

config.add_view(web, route_name='default')
config.add_view(api, route_name='api')

使用URL分派应该可以让你在应用程序的前缀中更简单地挂载东西。 URL分派中的路由按顺序匹配，因此请确保api在默认值之前运行，否则所有内容都将发送到默认路由。

金字塔如何设置api中间件？

1 个答案: