Question

如何解决以下问题：

var xvalue = from cust in list 
             where cust.DisplayString == ((Data)x).CustomerName 
             select cust.Number;
int namX = xvalue;

Answer 1

您的查询将始终返回匹配结果的“集合”，即使该集合仅返回单个项目。

如果您知道您的查询总是只匹配一个项目，则可以使用Single Linq方法：

var xvalue = from cust in list 
             where cust.DisplayString == ((Data)x).CustomerName 
             select cust.Number;
int namX = xvalue.Single();

Answer 2

你试过吗

int namX = Convert.ToInt32(namx.FirstOrDefault());

Answer 3

返回单个项目后，您还应获取该项目的属性，在本例中为Number

var xvalue = from cust in list 
             where cust.DisplayString == ((Data)x).CustomerName 
             select cust.Number;

int namX = xvalue.Single().Number;

Answer 4

if u are sure that the condition "cust.DisplayString == ((Data)x).CustomerName" will return only one record than u can use code below this will return one number. other wise please see the next tip.

int namX = (from cust in list 
             where cust.DisplayString == ((Data)x).CustomerName 
             select cust).ToList().FirstOrDefault().Number;

if after applying the condition results can be more than one than surely it will be a list of int so the below code will work.


List<int> namX = (from cust in list 
             where cust.DisplayString == ((Data)x).CustomerName 
             select cust.Number).ToList();

如何从linq获取int值

4 个答案: