我正在制作一个押韵词典,我有一个包含3个coloumns的数据库表,用户将搜索数据库,搜索关键词将搜索数据库,其中单词的结尾与文本框中的单词匹配。
当我在文本框中输入一些关键字时
我收到错误:关键字'LIKE'附近的语法不正确。
This is how my database looks like
以下是我的aspx的样子:
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title>Kafiye Dizini - Türkçe Kafiye Bulma Sözlüğü - Uyak Bulucu Sözlük - İstediğiniz harf ile biten kelimeleri bulan sözlük</title>
<meta name="description" content="İstediğiniz harfler ile biten kelimeleri bulmanızı sağlayan sözlük" />
<link rel="shortcut icon" type="image/x-icon" href="favicon.ico" />
<link href="style.css" rel="stylesheet" />
</head>
<body>
<form id="form1" runat="server">
<div>
<div class="top">
<div class="email">İletişim: fahrettinveysel@gmail.com</div>
</div>
<div class="leftcontainer">
</div>
<div class="middlecontainer">
<div class="title">Kafiye Dizini</div>
<div class="subtitle">İstediğiniz harf veya hece ile biten kelimeleri bulmanızı sağlayan sözlük</div>
<div class="searchcontainer">
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
</div>
<div class="resultboxcontainer">
<div id="resultbox1" runat="server"></div>
<div id="resultbox2" runat="server"></div>
<div id="resultbox3" runat="server"></div>
</div>
<div class="idefix"></div>
</div>
<div class="rightcontainer">
<div class="ornekarama">
<div class="ornekaramabaslik">Örnek Arama</div>
<input type="text" class="ornekaramatextbox" value="rop" disabled="disabled" />
<div class="ornekaramasonuclar">filantrop<br />gardırop<br />hipermetrop<br />mikrop<br />mizantrop</div>
</div>
</div>
</div>
</form>
</body>
</html>
这是我的aspx.cs
using System;
using System.Collections.Generic;
using System.Data.SqlClient;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
SqlConnection cnn = new SqlConnection("Initial Catalog=kafiyedizini;Data Source=localhost;Integrated Security=SSPI;");
protected void Button1_Click(object sender, EventArgs e)
{
if (TextBox1.Text != "")
{
cnn.Open();
SqlCommand cmd = new SqlCommand("SELECT kelime1,kelime2,kelime3 FROM kelimeler LIKE @arama", cnn);
cmd.Parameters.AddWithValue("@arama", "%" + TextBox1.Text);
SqlDataReader dr = cmd.ExecuteReader();
if (dr.HasRows)
{
while (dr.Read())
{
resultbox1.InnerHtml += dr.GetString(0);
resultbox2.InnerHtml += dr.GetString(1);
resultbox3.InnerHtml += dr.GetString(2);
}
}
cnn.Close();
}
else
{
resultbox1.InnerHtml += "please enter data";
}
}
}
答案 0 :(得分:0)
您缺少部分SQL查询
示例:
SELECT * FROM test WHERE test.Id LIKE '%asd%'
我也认为,dr.Read()执行PER ROW。
希望这有帮助
答案 1 :(得分:0)
您问题中的初始sql语句应如下所示
SELECT kelime1,kelime2,kelime3 FROM kelimeler where kelime1 LIKE @arama OR kelime2 LIKE @arama or kelime3 like @arama
你错过了你想要在你的声明中使用的地点和字段。
将每个结果放在一个单独的框中&#39;您可以更好地研究GridView的工作方式或DataRepeater。
最初的代码中最接近的可能是什么,包括支持处理返回字段的null / emtpy值,很好地填充3个结果框:
var f1 = dr.GetString(0);
var f2 = dr.GetString(1);
var f3 = dr.GetString(2);
if (!String.IsNullOrEmpty(f1))
resultbox1.InnerHtml += String.Format("<div>{0}</div>",f1);
if (!String.IsNullOrEmpty(f2))
resultbox2.InnerHtml += String.Format("<div>{0}</div>",f2);
if (!String.IsNullOrEmpty(f3))
resultbox1.InnerHtml += String.Format("<div>{0}</div>",f3);