嗨,所以我知道这是以前似乎已经回答过的事情,但我尝试过的任何事都没有奏效。基本上我要做的是调用一个插入一些数据的存储过程,并返回刚刚插入的auto_increment的id。然后该声明被关闭,我保留了id。
然后有趣的部分发生了。我进入一个循环,对于循环的每个实例,我需要调用另一个插入一些数据的存储过程,并返回最后一个auto_increment的id。使用该ID我将继续做更多的事情。但是,现在它在循环中失败了。它第一次执行没有问题,然后准备下一次绕过它给我错误Commands out of sync; you can't run this command now
。
我真的试图以某种方式释放第一次使用stmt-> free()的结果,但这不起作用,或者释放mysqli2连接,但我做的一切都没有奏效在此刻。任何提示或提示都会非常感激!
$insert_questionnaire_sql = "CALL insert_questionnaire_info(?, ?, ?, ?, ?, ?, ?)";
$questionnaire_insert_stmt = $mysqli->prepare($insert_questionnaire_sql);
$questionnaire_insert_stmt->bind_param("ssisiis", $meta[0], $meta[4], $length_of_questions, $user, $meta[2], $meta[3], $meta[1]);
//execute the statement
$success = $questionnaire_insert_stmt->execute();
$qn_id = -1;
//bind the id of the questionnaire that was just inserted
$questionnaire_insert_stmt->bind_result($qn_id);
//fetch the id
$questionnaire_insert_stmt->fetch();
//close the statement
$questionnaire_insert_stmt->close();
//next we insert each question into the database
$i = 0;
for($i; $i < count($Questions); $i++){
//only if the question has been submitted
if($Questions[$i]->submitted){
//prepare the statement
$insert_question_sql = "CALL insert_question_info(?, ?, ?, ?, ?, ?, ?)";
$question_insert_stmt = $mysqli2->prepare($insert_question_sql) or die ($mysqli2->error);
$type = -1;
$width = -1;
$height = -1;
//count the number of answers
$numAnswers = countNotDeletedAnswers($Questions[$i]);
$text = $Questions[$i]->text;
//figure out what kind of thing this is
if($Questions[$i]->instruction == true){
$type = 2;
}
else if($Questions[$i]->image == true){
$type = 3;
$width = $Questions[$i]->width;
$height = $Questions[$i]->height;
//if we have an image we want to put the path as the text
$text = $Questions[$i]->path;
}
else{
$type = 1;
}
//bind the params
$question_insert_stmt->bind_param("isiisii", $qn_id, $text, $type, $numAnswers, $user, $width, $height);
//execute
$success = $question_insert_stmt->execute() or die ($mysqli2->error);
//bind the id of the questionnaire that was just inserted
$q_id = -1;
$question_insert_stmt->bind_result($q_id);
//fetch the id
$data = $question_insert_stmt->fetch();
//close the statement
$question_insert_stmt->close();
}
}
答案 0 :(得分:1)
CALL
- 查询获取其他结果集,如docs中所述。在这样的查询之后尝试循环throght其他结果集并释放它们,使用类似这样的东西:
function cleanUp(mysqli_stmt $stmt)
{
do
{
// $stmt->store_result();
$stmt->free_result();
}
while($stmt->more_results() && $stmt->next_result());
}
否则,如果您的过程返回任何结果集,那么您将收到此错误,而该free()
正确无法{/ p}}。