指定UICollectionView的行号和列号

时间:2013-09-25 16:25:51

标签: ios uicollectionview uicollectionviewcell

我想显示一个UICollectionView,每行包含2行和100个单元格。

// 1
- (NSInteger)collectionView:(UICollectionView *)view numberOfItemsInSection:(NSInteger)section {

    return 100;
}
// 2
- (NSInteger)numberOfSectionsInCollectionView: (UICollectionView *)collectionView {
    return 2;
}
// 3
- (UICollectionViewCell *)collectionView:(UICollectionView *)cv cellForItemAtIndexPath:(NSIndexPath *)indexPath {
    MyCell *cell = [cv dequeueReusableCellWithReuseIdentifier:@"cell" forIndexPath:indexPath];

        cell.lbl.text = @"Data";

    return cell;
}

我得到了这个:

enter image description here

如何为UICollectionView指定行号?我想创建一个2x100表。

5 个答案:

答案 0 :(得分:16)

试试这个:

// 1
- (NSInteger)collectionView:(UICollectionView *)view numberOfItemsInSection:(NSInteger)section {

    return 2;
}
// 2
- (NSInteger)numberOfSectionsInCollectionView: (UICollectionView *)collectionView {
    return 100;
}
// 3
- (UICollectionViewCell *)collectionView:(UICollectionView *)cv cellForItemAtIndexPath:(NSIndexPath *)indexPath {
    MyCell *cell = [cv dequeueReusableCellWithReuseIdentifier:@"cell" forIndexPath:indexPath];

        cell.lbl.text = @"Data";

    return cell;
}

答案 1 :(得分:16)

每行3个单元格..添加此代码。

- (CGSize)collectionView:(UICollectionView *)collectionView layout:(UICollectionViewLayout *)collectionViewLayout sizeForItemAtIndexPath:(NSIndexPath *)indexPath
{
     return CGSizeMake(collectionView.frame.size.width/3.2 , 100);
}

答案 2 :(得分:11)

对于Swift 每列3行(使用@SakhshiSingla答案)

4786.6445

答案 3 :(得分:10)

在集合视图中实现与任何方向兼容的n列的更一般方法是

 func collectionView(collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, sizeForItemAtIndexPath indexPath: NSIndexPath) -> CGSize {

   // flow layout have all the important info like spacing, inset of collection view cell, fetch it to find out the attributes specified in xib file
   guard let flowLayout = collectionViewLayout as? UICollectionViewFlowLayout else {
        return CGSize()
    }

    // subtract section left/ right insets mentioned in xib view

    let widthAvailbleForAllItems =  (collectionView.frame.width - flowLayout.sectionInset.left - flowLayout.sectionInset.right)

    // Suppose we have to create nColunmns
    // widthForOneItem achieved by sunbtracting item spacing if any

    let widthForOneItem = widthAvailbleForAllItems / nColumns - flowLayout.minimumInteritemSpacing


    // here height is mentioned in xib file or storyboard
    return CGSize(width: CGFloat(widthForOneItem), height: (flowLayout.itemSize.height))
 }

答案 4 :(得分:3)

部分数量决定每行中有多少个单元格,假设单元格大小允许它。

一个部分将始终开始一个新行。