Question

我正在为我的应用使用经过身份验证的网页浏览。有一个关于搜索字词的网址，这样如果您在搜索框中输入了abc，则会调用网址“http://something.com/something/ ABC /东西”。它加载正常，直到我有一个无效的searchterm，如果我输入“INVALIDCRAP”，它仍然会将网址设为“http://something.com/something/ INVALIDCRAP /某事，并尝试加载它，从而给我一个412前提条件错误。我想这样做，以防标识符“INVALIDCRAP”不存在，而不是412前提条件错误，它将重定向我说“google.com”。任何关于如何去做的想法？提前谢谢这是我的相同代码：

 @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);

            Bundle bundle = this.getArguments();
            URL = getUrl();

            if(bundle != null)
                mSearchTerm = getArguments().getString(SEARCH_TERM);

             }
     public void setSearchTerms(String sTerms){
         mSearchTerm = sTerms;
     }
private static String getUrl(){
        String url = "";

        final String getuuid = SharedPreferencesManager.getInstance().getUUID();
        final String environmentApi = SharedPreferencesManager.getInstance().getEnvironmentApi();
        if (environmentApi.equalsIgnoreCase(NetworkUtils.Apis.ALPHA)) {
            "https://something.com/service/v1/?q="+mSearchTerm+"%20revenue&ui.theme=novadark&uuid="+getuuid+"&userAgent=android";



        }


@Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        if (goingBack) {
            return null;
        }
        final MainActivity activity = (MainActivity) getActivity();
        final Resources resources = Application.getAppResources();

        activity.setBackPressListener(this);
        View view = inflater.inflate(R.layout.fragment_search_answers, container, false);


        mWebview =  (WebView)view.findViewById(R.id.webview);
        progressBar = (LinearLayout) view.findViewById(R.id.loading);   
        mWebview.setVisibility(View.VISIBLE);

        progressBar.setVisibility(View.VISIBLE);

            mWebview.setWebViewClient(new MyWebViewClient(this, mWebview));

            mWebview.setBackgroundColor(0);
            mWebview.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
            mWebview.getSettings().setAllowFileAccess(true);
            mWebview.getSettings().setDomStorageEnabled(true);
            mWebview.getSettings().setJavaScriptEnabled(true);

            mWebview.setHttpAuthUsernamePassword(HOST, REALM, USERNAME, PASSWORD);
            mWebview.setScrollbarFadingEnabled(false);
            mWebview.getSettings().getLoadsImagesAutomatically();


            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB)
            mWebview.getSettings().setDisplayZoomControls(false);
            if(StringUtils.isEmpty(URL)){

            }else if(!StringUtils.isEmpty(URL)){


                if(URLUtil.isValidUrl(URL)){
                     mWebview.loadUrl(URL);
                }else{
                    mWebview.loadUrl("http://www.google.com");


                }

            }



        return view;
    }

  public class MyWebViewClient extends WebViewClient {
        private String loginCookie;
        public MyWebViewClient(AnswersWebViewFragment answersWebViewFragment, WebView webview) {
            super();
        }
        @Override
        public void onPageStarted(WebView view, String url, Bitmap favicon) {
            view.setVisibility(View.VISIBLE);

        }

        @Override
        public void onPageFinished(WebView view, String url) {
            view.setVisibility(View.VISIBLE);
            CookieManager cookieManager = CookieManager.getInstance();
            cookieManager.setCookie(url, loginCookie);
            final Animation fade = new AlphaAnimation(0.0f, 1.0f);
            fade.setDuration(200);
            view.startAnimation(fade);
            view.setVisibility(View.VISIBLE);
            progressBar.setVisibility(View.GONE);

        }
        @Override
        public void onReceivedError( WebView view, int errorCode, String description, String failingUrl ) {
            Toast.makeText(view.getContext(), "Authentication Error", Toast.LENGTH_LONG).show();
            super.onReceivedError(view, errorCode, description, failingUrl);
        }

        @Override
        public void onLoadResource( WebView view, String url ){

        }
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {

                return super.shouldOverrideUrlLoading(view, url);


        }


        @Override
        public void onReceivedHttpAuthRequest( WebView view, final HttpAuthHandler handler, final String host, final String realm ){
                handler.proceed(USERNAME,PASSWORD);

    }

         @Override
        public void onReceivedSslError( WebView view, SslErrorHandler handler, SslError error ) {
            handler.proceed();
        }

    }

这是相同的屏幕： enter image description here

Answer 1

如果确实没有调用onReceivedError，那么我认为只有一个选项（并且只有在您控制网站的情况下）。如果412发生，只要假设标题将包含例如“服务器错误”。

...your code

webview.setWebChromeClient(new WebChromeClient() {
   @Override
   public void onReceivedTitle(WebView view, String title) {
      super.onReceivedTitle(view, title);

      String serverError = "ServerError";
      if (title.contains(serverError)) {
          view.stopLoading();
          webview.loadUrl(getNewUrl());
      }
   }
});

public String getNewUrl(){
   //do your stuff here
   return "http://www.google.com";
}

如何在android webview url中检测412个前提条件失败的错误

1 个答案: