我想知道如何将以下容器复制到临时变量,以及如何定义该临时变量。
const char *containers_1[] = {"one","two","why do I stuck in this problem"};
const char *containers_2[] = {"Other","string","here"};
所以我正在寻找一个合适类型的临时变量,我可以将其中一个容器复制到。 "const char * container []"
的声明来自一段我不想改变以保持格式的代码!
感谢您的时间。
答案 0 :(得分:1)
代码应该改进,但我认为这就是你想要的。
const char *containers_1[] = {"one","two","why do I stuck in this problem"};
const char *containers_2[] = {"Other","string","here","whis","has","more"};
main(int argc, char **argv) {
char ** tmp1;
int i, size;
size = sizeof(containers_1);
printf ("%d\n", size);
tmp1 = malloc(size);
memcpy(tmp1, containers_1, sizeof(containers_1));
for (i=0; i< size/sizeof(char *); i++) {
printf("%s\n", tmp1[i]);
}
size = sizeof(containers_2);
printf ("%d\n", size);
tmp1 = malloc(size);
memcpy(tmp1, containers_2, sizeof(containers_2));
for (i=0; i< size/sizeof(char *); i++) {
printf("%s\n", tmp1[i]);
}
}