Question

编辑：大家好，

我想通了

select LI.ProjectId, count(*) as numLineItems
into #temp
from dbo.SQLLineItems as LI
group by LI.ProjectId
having COUNT(*) < =200

select numLineItems, count(*), SUM(PT.GrandTotalSell) from
#temp
inner join dbo.SQLProjectTotals as PT
on PT.ProjectId = #temp.ProjectId
group by numLineItems;

感谢您的帮助。

我有两个包含项目信息的表。表1包含LineItems，每个LineItem都具有该表唯一的GUID和ProjectID的GUID。每个ProjectID都有重复项，因为一个ProjectID可以有多个LineItem。

表2按项目ID链接到表1，GUID在该表中是唯一的。表2还包含每个项目的价格。

我想按LineItem的数量细分项目，看看有多少项目是1,2,3,4 ......项目项目。

我写了一个有效的查询：

use FieldedProjects;

select LI.ProjectId, count(*) as numLineItems
into #temp
from dbo.SQLLineItems as LI
group by LI.ProjectId
having COUNT(*) < =15

select numLineItems, count(*) from
#temp
group by numLineItems;

但现在我想修改它以显示价格总计。因此，1个项目项目的总项目价格为100,2个项目项目为300，...

我在想像

这样的东西

use FieldedProjects;

select LI.ProjectId, count(*) as numLineItems, SUM(PT.GrandTotalSell) as projectTotal
into #temp
from dbo.SQLLineItems as LI
inner join dbo.SQLProjectTotals as PT
on LI.ProjectID = PT.ProjectID
group by LI.ProjectId
having COUNT(*) < =15

select numLineItems, count(*), projectTotal from
#temp
group by numLineItems;

但是它给了我一个错误，因为projectTotal不包含在聚合函数中。它应该是

select numLineItems, count(*), SUM(projectTotal) from

Answer 1

select *
from dbo.SQLProjectTotals as PT
cross apply
(
    select count(*)
    from dbo.SQLLineItems LI
    where LI.ProjectID = PT.ProjectID
) items(Count)
where items.Count <= 15

T-SQL计算与GUID关联的字段数，并从另一个与相同GUID关联的表中获取字段总和

1 个答案: