Question

我有一个长字符串，其中包含需要分离/提取以供评估的信息集。

作为初学程序员，我知道各种解析操作，例如split（）append（）remove（）等 - 但我正在努力想出一种逻辑方法来组合它们来提取相关数据......

长串......

"<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>"

包含需要存储为浮点值的3组数据

[Set1] s = 1 e = 2176 t = -20774 r = 1

[Set2] s = 2177 e = 8982 t = -18597 r = 1

[Set3] s = 8983 e = 10393 t = -150.2 r = 1

我希望将每组数据存储为列表

Set1 = [1,2176,-20774,1]
Set2 = [2177,8982,-18597,1]
Set3 = [2178,10393,-150.2,1]

注意：套数可以变化

Answer 1

使用内置的ElementTree库从xml中提取数据：

import xml.etree.ElementTree as ET


data = '<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>'

tree = ET.fromstring(data)
for b in tree.findall('.//B'):
     print map(float, itemgetter(*'setr')(b.attrib))

打印：

[1.0, 2176.0, -20774.0, 1.0]
[2177.0, 8982.0, -18597.0, 1.0]
[8983.0, 10393.0, -150.22, 1.0]

Answer 2

注意：这是之前答案的延伸......

（支持@alecxe和@Jon Clements）

为了标记每个数据集并以易于访问的格式存储结果

import xml.etree.ElementTree as ET
import operator

data = '<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>'

dataDictionary = {}

tree = ET.fromstring(data)
setNumber = 0

for b in tree.findall('.//B'):
    setNumber = setNumber + 1
    dataSet = map(float, operator.itemgetter(*'setr')(b.attrib))
    dataDictionary[setNumber] = dataSet
    print "This is dataset " +str(setNumber)
    print dataSet

print ""
print "This is the Dictionary of datasets"
print dataDictionary

这导致以下输出 - 这对于将来的操作很容易使用：）

This is dataSet 1
[1.0, 2176.0, -20774.0, 1.0]
This is dataSet 2
[2177.0, 8982.0, -18597.0, 1.0]
This is dataSet 3
[8983.0, 10393.0, -150.22, 1.0]

This is the dataDictionary
{1: [1.0, 2176.0, -20774.0, 1.0], 2: [2177.0, 8982.0, -18597.0, 1.0], 3: [8983.0, 10393.0, -150.22, 1.0]}

解析数据集的字符串

2 个答案: