我试图对涉及变量的公式进行简单的数学计算。但是,编译器中会弹出一个错误,指示变量类型不匹配。我已经尝试过转换和更改变量类型,但它们不起作用。如何解决这个问题而不破坏我的代码的基本格式。
我没有Java经验,所以任何指针都会有所帮助。
这是代码。这是一个货币兑换计划。错误发生在代码的第二部分,即else部分。
import java.util.Scanner;
public class MConvert
{
public static void main (String[] args)
{
int penny, nickel, dime, quarter, halfDollar, dollar, fiveDollar, tenDollar, twentyDollar, fiftyDollar, hundredDollar;
//can sub $ sign for dollar in variable, convention otherwise
double totalMoney;
Scanner scan = new Scanner (System.in);
System.out.println ("Are you converting to the total? If so, type true. \nIf you are converting from the total, then type false.");
boolean TotalorNot = true;
TotalorNot = scan.nextBoolean();
if (TotalorNot) {
System.out.println ("Type in the number of one-hundred dollar bills.");
hundredDollar = scan.nextInt();
System.out.println ("Type in the number of fifty dollar bills.");
fiftyDollar = scan.nextInt();
System.out.println ("Type in the number of twenty dollar bills.");
twentyDollar = scan.nextInt();
System.out.println ("Type in the number of ten dollar bills.");
tenDollar = scan.nextInt();
System.out.println ("Type in the number of five dollar bills.");
fiveDollar = scan.nextInt();
System.out.println ("Type in the number of one dollar bills or coins.");
dollar = scan.nextInt();
System.out.println ("Type in the number of half-dollar coins.");
halfDollar = scan.nextInt();
System.out.println ("Type in the number of quarter-dollar coins.");
quarter = scan.nextInt();
System.out.println ("Type in the number of dimes.");
dime = scan.nextInt();
System.out.println ("Type in the number of nickels.");
nickel = scan.nextInt();
System.out.println ("Type in the number of pennies coins.");
penny = scan.nextInt();
totalMoney = (hundredDollar * 100) + (fiftyDollar * 50) + (twentyDollar * 20) + (tenDollar * 10) + (fiveDollar * 5) + (dollar * 1) + ((double)halfDollar * 0.5) + ((double)quarter * 0.25) + ((double)dime * 0.1) + ((double)nickel * 0.05) + ((double)penny * 0.01);
System.out.println ("Here is total monetary value of the bills and coins you entered: " + totalMoney);
} else {
System.out.println ("Type in the total monetary value:");
totalMoney = scan.nextDouble();
hundredDollar = ((int)totalMoney / 100);
fiftyDollar = ((int)totalMoney - (hundredDollar * 100)) / 50;
twentyDollar = ((int)totalMoney - (fiftyDollar * 50)) / 20;
tenDollar = ((int)totalMoney - (twentyDollar * 20)) / 10;
fiveDollar = ((int)totalMoney - (tenDollar * 10)) / 5;
dollar = ((int)totalMoney - (fiveDollar * 5)) / 1;
(double) halfDollar = (totalMoney - (dollar * 1)) / 0.5;
quarter = ((int)totalMoney - (halfDollar * 0.5)) / 0.25;
dime = ((int)totalMoney - (quarter * 0.25)) / 0.1;
nickel = ((int)totalMoney - (dime * 0.1)) / 0.05;
penny = ((int)totalMoney - (nickel * 0.05)) / 0.01;
System.out.println (hundredDollar + " hundred dollar bills");
System.out.println (fiftyDollar + " fifty dollar bills");
System.out.println (twentyDollar + " twenty dollar bills");
System.out.println (tenDollar + " ten dollar bills");
System.out.println (fiveDollar + " five dollar bills");
System.out.println (dollar + " one dollar bills or coins");
System.out.println (halfDollar + " half-dollar coins");
System.out.println (quarter + " quarter-dollar coins");
System.out.println (dime + " dimes");
System.out.println (nickel + " nickel");
System.out.println (penny + " penny");
}
}
}
答案 0 :(得分:1)
(double) halfDollar = (totalMoney - (dollar * 1)) / 0.5;
完全错误,首先删除此说明。
还可以使用以下行更改您的代码。
quarter = (int)((totalMoney - (halfDollar * 0.5)) / 0.25);
dime = (int) ((totalMoney - (quarter * 0.25)) / 0.1);
nickel =(int)( (totalMoney - (dime * 0.1)) / 0.05);
penny = (int)((totalMoney - (nickel * 0.05)) / 0.01);
您还需要改进代码的逻辑,我可以清楚地看到它不能满足您的目标。
答案 1 :(得分:0)
在这一行 ((int)totalMoney - (tenDollar * 10))/ 5;
演员表仅应用于totalMoney
要转换整个表达式的值,你必须这样做
(int)(totalMoney - (tenDollar * 10)) / 5);
答案 2 :(得分:0)
问题出在以下几行:
(double) halfDollar = (totalMoney - (dollar * 1)) / 0.5;
这里(double)
的含义是什么?您不能将变量赋值的左侧(变量本身)强制转换为double。该变量被声明为int,并且无法更改。从不。
这一行编译(但可能与语义不一致):
halfDollar = (int) ((totalMoney - (dollar * 1)) / 0.5);
除此之外:我不认为,程序会这样做,你想要它做什么......
答案 3 :(得分:0)
(double) halfDollar = (totalMoney - (dollar * 1)) / 0.5;
你想通过halfDollar上的双重演员实现什么?首先删除它。我花了5分钟才找出你的代码中有这么多红线的原因。
接下来,你可以做一个这样的简单案例: -
halfDollar = (int)((totalMoney - (dollar * 1)) / 0.5);
但不建议将双值转换为int,因为您可能会丢失大量的十进制数据。为什么不简单地将所有penny, nickel, dime, quarter, halfDollar, dollar, fiveDollar, tenDollar,twentyDollar, fiftyDollar, hundredDollar;
作为double
本身?