Question

是否可以返回type of an entities（例如位置）就像freebase search的工作方式一样？我正在使用freebase搜索示例代码（我将在下面提供它们）来生成搜索结果，但即使使用通配符，它也不会提取实体类型，这里有一些示例结果。

样本结果

["\/en\/bukit_panjang","Bukit Panjang",284.883636,"\/m\/04fxxf","en"]
["\/en\/bukit_panjang_mrt_station",{"id":"\/metropolitan_transit\/transit_stop","name":"Transit Stop"},"Bukit Panjang LRT\/MRT Station",250.857147,"\/m\/0661mk1","en"]
["\/en\/bukit_panjang_plaza",{"id":"\/business\/shopping_center","name":"Shopping center"},"Bukit Panjang Plaza",229.566818,"\/m\/02q_h6s","en"]

搜索示例代码

import com.google.api.client.http.GenericUrl;
import com.google.api.client.http.HttpRequest;
import com.google.api.client.http.HttpRequestFactory;
import com.google.api.client.http.HttpResponse;
import com.google.api.client.http.HttpTransport;
import com.google.api.client.http.javanet.NetHttpTransport;
import com.jayway.jsonpath.JsonPath;
import java.io.FileInputStream;
import java.util.Properties;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;

public class SearchSample {
  public static Properties properties = new Properties();
  public static void main(String[] args) {
    try {
      properties.load(new FileInputStream("freebase.properties"));
      HttpTransport httpTransport = new NetHttpTransport();
      HttpRequestFactory requestFactory = httpTransport.createRequestFactory();
      JSONParser parser = new JSONParser();
      GenericUrl url = new GenericUrl("https://www.googleapis.com/freebase/v1/search");


      url.put("query", "Bukit Panjang");
      //url.put("filter", "(any type:/people/person domain:location/citytown/)");
      url.put("filter", "(any part_of:singapore)");


      url.put("limit", "10");
      url.put("indent", "true");
      url.put("key", properties.get("API_KEY"));
      HttpRequest request = requestFactory.buildGetRequest(url);
      HttpResponse httpResponse = request.execute();
      JSONObject response = (JSONObject)parser.parse(httpResponse.parseAsString());
      JSONArray results = (JSONArray)response.get("result");
      for (Object result : results) {
        System.out.println(JsonPath.read(result,"$.*").toString());
      }
    } catch (Exception ex) {
      ex.printStackTrace();
    }
  }
}

Answer 1

使用output参数来定制输出，如本页所述：

https://developers.google.com/freebase/v1/search-output

e.g。

https://www.googleapis.com/freebase/v1/search?indent=true&filter=%28all+name%7Bfull%7D%3A%22Bukit+Panjang%22+part_of:singapore%29&output=%28type%29

（尽管您可能需要考虑使用notable_type或notable_for代替原始类型，具体取决于您的目标）

Freebase searchAPI返回类型

1 个答案: