我有一个像这样的表架构
的MySQL＆GT; desc material_out;
`enter code here` +-------------+--------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------------+--------------+------+-----+---------+-------+ | id | int(11) | NO | | 0 | | | barcode | varchar(20) | NO | | NULL | | | name | varchar(100) | NO | | NULL | | | qty | double | YES | | NULL | | | unit | varchar(20) | YES | | NULL | | | num_letter | varchar(30) | YES | | NULL | | | date | date | YES | | NULL | | | destination | varchar(50) | YES | | NULL | | +-------------+--------------+------+-----+---------+-------+ 8 rows in set (0.00 sec)
的MySQL＆GT; desc material_in;
`enter code here` +-------------+--------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------------+--------------+------+-----+---------+-------+ | id | int(11) | NO | | 0 | | | barcode | varchar(20) | NO | | NULL | | | name | varchar(100) | NO | | NULL | | | qty | double | YES | | NULL | | | unit | varchar(20) | YES | | NULL | | | num_letter | varchar(30) | YES | | NULL | | | date | date | YES | | NULL | | | destination | varchar(50) | YES | | NULL | | +-------------+--------------+------+-----+---------+-------+ 8 rows in set (0.00 sec)
的MySQL＆GT; desc goods;
`enter code here` +-------------+--------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------------+--------------+------+-----+---------+-------+ | id | int(11) | NO | | 0 | | | barcode | varchar(20) | NO | | NULL | | | name | varchar(100) | NO | | NULL | | | unit | varchar(20) | YES | | NULL | | | category | varchar(25) | YES | | NULL | | | first_stok | double ) | YES | | NULL | | +-------------+--------------+------+-----+---------+-------+ 6 rows in set (0.00 sec)
在表material_out中，我有10,000行的数据。并有多达350种条形码。 在表material_in中，我有大约15,000行的数据。并且有多达200种条形码。
但我在进行查询时遇到问题。需要很长时间大约3个小时。
我认为当您想要打印报告时效率不高。
我这样的查询。
SELECT br.barcode,
out.total_out,
in.total_in,
out.total_out - in.total_in AS RESULT
FROM
(SELECT barcode,
name,
first_stok,
unit
FROM goods
WHERE category=1) AS br
LEFT JOIN
(SELECT
(SELECT sum(qty)
FROM material_out
WHERE date >= '2013-08-15'
AND tanggal <='2013-08-20'
AND barcode=a.barcode) AS total_out
FROM material_out a
GROUP BY a.barcode) AS OUT ON OUT.barcode=br.barcode
LEFT JOIN
(SELECT
(SELECT sum(qty)
FROM material_in
WHERE date >= '2013-08-15'
AND tanggal <='2013-08-20'
AND barcode=a.barcode) AS total_in
FROM material_in a
GROUP BY a.barcode) AS IN ON IN.barcode=br.barcode
编辑兄弟.. 来自realitygone的新查询。
<pre>
mysql> SELECT tNEW.barcode,
-> tNEW.total_out, tNEW.total_in, tNEW.result,
-> tOLD.total_out AS total_out_old, tOLD.total_in AS total_in_old, tNEW.total_in + tOLD.total_in - tNEW.total_out - tOLD.total_out as sum_total
-> FROM (
-> SELECT goods.barcode,
-> SUM(tOUT.qty) AS total_out,
-> SUM(tIN.qty) AS total_in,
-> SUM(tIN.qty) - SUM(tOUT.qty) AS result
-> FROM goods
-> LEFT JOIN material_out AS tOUT ON tOUT.barcode=goods.barcode
-> LEFT JOIN material_in AS tIN ON tIN.kode=goods.barcode
-> WHERE goods.category=1
-> AND tOUT.date BETWEEN '2013-05-01' AND '2013-08-31'
-> AND tIN.date BETWEEN '2013-05-1' AND '2013-08-31'
-> GROUP BY goods.barcode
-> ) AS tNEW
-> LEFT JOIN (
-> SELECT goods.barcode,
-> SUM(tOUT.qty) AS total_out,
-> SUM(tIN.qty) AS total_in
-> FROM goods
-> LEFT JOIN material_out AS tOUT ON tOUT.barcode=goods.barcode
-> LEFT JOIN material_in AS tIN ON tIN.kode=goods.barcode
-> WHERE goods.category=1
-> AND tOUT.date BETWEEN '2013-01-01' AND '2013-04-31'
-> AND tIN.date BETWEEN '2013-01-01' AND '2013-04-31'
-> GROUP BY goods.barcode
-> ) AS tOLD ON tOLD.barcode=tNEW.barcode;
+-------------+-----------+----------+------------+---------------+-------------------+--------------------+
| barcode | total_out | total_in | result | total_out_old | total_in_old | sum_total |
+-------------+-----------+----------+------------+---------------+-------------------+--------------------+
| CG003 | 2720 | 14400 | 11680 | 17588 | 92160 | 86252 |
| CG009 | 144 | 720 | 576 | NULL | NULL | NULL |
| CG010 | 596 | 1800 | 1204 | 1512 | 6048 | 5740 |
| CG011 | 864 | 4320 | 3456 | 1156 | 3600 | 5900 |
| CG012 | 1875 | 7560 | 5685 | 843 | 4680 | 9522 |
| CG013 | 2520 | 7560 | 5040 | 2826 | 14400 | 16614 |
| CG014 | 19320 | 314340 | 295020 | 39312 | 597312 | 853020 |
| CG015 | 890 | 9750 | 8860 | 12003 | 183330 | 180187 |
| CG017 | 24 | 102000 | 101976 | 26 | 420 | 102370 |
| CG018 | 390000 | 273000 | -117000 | 1320000 | 1020000 | -417000 |
| CG020 | 396 | 2170 | 1774 | 820 | 3656 | 4610 |
| CG022 | 238 | 1200 | 962 | 330 | 800 | 1432 |
| CG023 | 752 | 3600 | 2848 | 3585 | 21600 | 20863 |
| CG024 | 21560 | 146068 | 124508 | 64095 | 361552.6000000002 | 421965.6000000002 |
| CG025 | 14833 | 85992 | 71159 | 49049 | 230218.0000000009 | 252328.00000000093 |
| CG026 | 172 | 4000 | 3828 | 766 | 1170 | 4232 |
| CG028 | 126 | 1440 | 1314 | 41 | 660 | 1933 |
| CG029 | 18 | 300 | 282 | 40 | 920 | 1162 |
| CG030 | 50 | 720 | 670 | 50 | 780 | 1400 |
| CHDRY001 | 10260 | 81000 | 70740 | 73440 | 936000 | 933300 |
| CHDRY002 | 4071288 | 3477926 | -593362 | 9762598 | 8570238 | -1785722 |
| CHDRY003 | 8880 | 4441 | -4439 | NULL | NULL | NULL |
| CHDRY004 | 48960 | 238590 | 189630 | 119880 | 413850 | 483600 |
| CHDRY005 | 144 | 144 | 0 | 256 | 256 | 0 |
| CHDRY006 | 37440 | 211200 | 173760 | 164160 | 968000 | 977600 |
| CHDRY007 | 237600 | 1679040 | 1441440 | 604890 | 4758600 | 5595150 |
| CHDRY009 | 766080 | 2026160 | 1260080 | 698250 | 2151560 | 2713390 |
| CHDRY010 | 3600 | 168000 | 164400 | 40800 | 1488000 | 1611600 |
| CHDRY012 | 200 | 2700 | 2500 | 340 | 5600 | 7760 |
| CHDRY013 | 4290 | 17600 | 13310 | 4290 | 21120 | 30140 |
| CHDRY014 | 278300 | 643720 | 365420 | 466210 | 1243620 | 1142830 |
| CHDRY015 | 78720 | 264100 | 185380 | 81840 | 367070 | 470610 |
| CHDRY018 | 2431270 | 1987260 | -444010 | 4877450 | 4672689 | -648771 |
| CHDRY022 | 1320 | 4840 | 3520 | 330 | 1650 | 4840 |
| CHDRY023 | 200 | 110 | -90 | NULL | NULL | NULL |
| CHDRY024 | 2000 | 4000 | 2000 | 100 | 100 | 2000 |
| CHDRY025 | 1800 | 4000 | 2200 | NULL | NULL | NULL |
| CHDRY026 | 850 | 850 | 0 | NULL | NULL | NULL |
| CHDRY028 | 120 | 480 | 360 | NULL | NULL | NULL |
| CHPRINT001 | 8000 | 222000 | 214000 | 13800 | 390000 | 590200 |
| CHPRINT002 | 4000 | 10000 | 6000 | 4200 | 21000 | 22800 |
| CHPRINT004 | 13600 | 324000 | 310400 | 14400 | 512000 | 808000 |
| CHPRINT005 | 28800 | 136800 | 108000 | 35000 | 133000 | 206000 |
| CHPRINT006 | 3100 | 93000 | 89900 | 5600 | 112000 | 196300 |
| CHPRINT007 | 16800 | 69000 | 52200 | 2000 | 9000 | 59200 |
------------------------------------------------------------------------------------------------------------
</pre>
tNEW.total_in + tOLD.total_in - tNEW.total_out - tOLD.total_out.时
当遇到列包含null时，sum的结果包含null。
例如在
条形码CHDRY025
条形码CHDRY003
条形码CHDRY028
条形码NWDRY004
对于管理员或主持人，对不起，如果我违反规则。 ： - ）
====================== 2013年9月30日发布的帖子==================== ==================
Hello RealityGone， 我使用了你的查询。结果进展顺利。但是当我尝试输入新数据时然后我重新查询你的显示器。但结果与输入的数据不符。 例如，当我从您输入查询时。以下结果
+----------------------+-----------+----------+------------+---------------+-------------------+ | barcode | total_out | total_in | result | total_out_old | total_in_old | +----------------------+-----------+----------+------------+---------------+-------------------+ | TNWET021 | 6195 | 15000 | 8805 | 20085 | 46200 | | TNWET020 | 3420 | 7650 | 4230 | 4860 | 23925 | | TNWET019 | 8370 | 25200 | 16830 | 11610 | 47175 | | TNWET018 | 18690 | 44100 | 25410 | 13800 | 54150 | | TNWET017 | 1140 | 3750 | 2610 | 3690 | 16200 | | TNWET016 | 19500 | 56100 | 36600 | 31725 | 111300 | | TNWET015 | 5145 | 18150 | 13005 | 6510 | 23400 | | TNWET014 | 33300 | 65250 | 31950 | 96300 | 262500 | | TNWET013 | 1170 | 5625 | 4455 | 3690 | 13200 | | TNWET012 | 720 | 2700 | 1980 | 3870 | 13800 | | TNWET011 | 0 | 0 | 0 | 180 | 450 | | TNWET010 | 0 | 0 | 0 | 405 | 1125 | | TNWET009 | 0 | 0 | 0 | 0 | 0 |
当我进行手动求和并得到这样的结果时。
mysql> select sum(qty) from material_in where barcode='TNWET021' and date BETWEEN '2013-05-01' AND '2013-08-31'; +-------------+ | sum(qty) | +-------------+ | 750 | +-------------+ 1 row in set (0.00 sec) mysql> select sum(qty) from material_in where barcode='TNWET020' and date BETWEEN '2013-05-01' AND '2013-08-31'; +-------------+ | sum(qty) | +-------------+ | 450 | +-------------+ 1 row in set (0.00 sec)
答案 0 :(得分：1)
我不认为你的查询甚至做了我认为它应该做的事情。您没有在问题中指定您期望的输出，但我假设您希望商品表中每个条形码的两个材料表中的qty字段的SUM（）。 （我还假设'tanggal'字段与它上面的日期字段相同，因为它不在您的EXPLAIN输出中，它表示英文日期。）
您当然不需要要加入的表表达式的SELECT语句中的子查询。我也不明白为什么那些需要成为表表达式。查询运行得非常慢，我并不感到惊讶。它是连接表表达式中的相关子查询。
我认为你根本不需要子查询。这是我的简化版本：
SELECT goods.barcode,
SUM(tOUT.qty) AS total_out,
SUM(tIN.qty) AS total_in,
SUM(tOUT.qty)-SUM(tIN.qty) AS result
FROM (
产品 LEFT JOIN material_out AS tOUT on tOUT.barcode = goods.barcode LEFT JOIN material_in AS tIN ON tIN.barcode = goods.barcode 在哪里g.category = 1 并且关于'2013-08-15'和'2013-08-20'之间的关系 和'2013-08-15'和'2013-08-20'之间的关系 GROUP BY g.barcode
可能有更好的方法可以做到这一点，但这就是我如何快速将两个日期范围放在一起，就像你问的那样：
SELECT tNEW.barcode,
tNEW.total_out, tNEW.total_in,
tNEW.total_out-tNEW.total_in AS result,
COALESCE(tOLD.total_out,0) AS total_out_old, COALESCE(tOLD.total_in,0) AS total_in_old
FROM (
SELECT g.barcode,
COALESCE(SUM(tOUT.qty),0) AS total_out,
COALESCE(SUM(tIN.qty),0) AS total_in
FROM (
SELECT DISTINCT barcode
FROM goods
) AS g
LEFT JOIN material_out AS tOUT ON tOUT.barcode=g.barcode
LEFT JOIN material_in AS tIN ON tIN.barcode=g.barcode
WHERE g.category=1
AND tOUT.date BETWEEN '2013-08-15' AND '2013-08-20'
AND tIN.date BETWEEN '2013-08-15' AND '2013-08-20'
GROUP BY g.barcode
) AS tNEW
LEFT JOIN (
SELECT g.barcode,
SUM(tOUT.qty) AS total_out,
SUM(tIN.qty) AS total_in
FROM (
SELECT DISTINCT barcode
FROM goods
) AS g
LEFT JOIN material_out AS tOUT ON tOUT.barcode=g.barcode
LEFT JOIN material_in AS tIN ON tIN.barcode=g.barcode
WHERE g.category=1
AND tOUT.date BETWEEN '2013-01-01' AND '2013-04-31'
AND tIN.date BETWEEN '2013-01-01' AND '2013-04-31'
GROUP BY g.barcode
) AS tOLD ON tOLD.barcode=tNEW.barcode