Question

我有以下数组：

Array
(
    [0] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55
        )

    [1] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55
        )

    [2] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55
        )

    [3] => Array
        (
            [Vendor_ID] => 3
            [Quantity] => 
        )

    [4] => Array
        (
            [Vendor_ID] => 3
            [Quantity] => 
        )

    [5] => Array
        (
            [Vendor_ID] => 3
            [Quantity] => 
        )

    [6] => Array
        (
            [Vendor_ID] => 4
            [Quantity] => 
        )

    [7] => Array
        (
            [Vendor_ID] => 4
            [Quantity] => 
        )

    [8] => Array
        (
            [Vendor_ID] => 4
            [Quantity] => 
        )

)

使用以下代码创建：

$Display_Arr = array();
        $Tick = 0;
    foreach ($_POST['product'] AS $_1){
        if (!in_array($_1['vendor_id'], $Display_Arr)){
            $Display_Arr[$Tick] = array(
                "Vendor_ID" => $_1['vendor_id'],
                "Quantity" => ""
            );
            $Display_Arr[$Tick]["Quantity"] .= $_1['quantity']; 
        }else{
            $Display_Arr[$Tick]["Quantity"] .= $_1['quantity']; 
        }
        ++$Tick;
    }
    echo "<pre>";
    print_r($Display_Arr);
    echo "</pre>";

但我没有得到我想要的输出，即：

Array
(
    [0] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55,55,55
        )


    [1] => Array
        (
            [Vendor_ID] => 3
            [Quantity] => 
        )


    [2] => Array
        (
            [Vendor_ID] => 4
            [Quantity] => 
        )

)

我在哪里错了？

@mathielo

目前的输出是：

Array
(
    [1] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55
        )

    [3] => Array
        (
            [Vendor_ID] => 3
            [Quantity] => 
        )

    [4] => Array
        (
            [Vendor_ID] => 4
            [Quantity] => 
        )

)

然而，我正试图获得：

    [0] => Array
        (
            [Vendor_ID] => 1
            [Quantity] => 55,55,55
        )

Answer 1

如果我做对了，你需要的是：

编辑：这次做了一些测试并且做对了：

$Display_Arr = array();
foreach ($_POST['product'] AS $_1){
    if (!array_key_exists($_1['Vendor_ID'], $Display_Arr)){
        $Display_Arr[$_1['Vendor_ID']] = array(
            "Vendor_ID" => $_1['Vendor_ID'],
            "Quantity" => $_1['Quantity']
        );
    }else{
        if(!empty($_1['Quantity']))
            $Display_Arr[$_1['Vendor_ID']]["Quantity"] .= ",{$_1['Quantity']}"; 
    }

}
echo "<pre>";
print_r($Display_Arr);
echo "</pre>";

主要问题出在if (!in_array($_1['vendor_id'], $Display_Arr))。 PHP的in_array()检查数组值中给定的needle，我们尝试匹配外部数组键中存储的Vendor_ID值< / em>的。这是使用array_key_exists()修复的。

编辑2：我将此用于测试数据：

$_POST['product'] = array( 0 => array( 'Vendor_ID' => 1, 'Quantity' => 55 ), 1 => array( 'Vendor_ID' => 1, 'Quantity' => 55 ), 2 => array( 'Vendor_ID' => 1, 'Quantity' => 55 ) , 3 => array( 'Vendor_ID' => 3, 'Quantity' => '' ), 4 => array( 'Vendor_ID' => 3, 'Quantity' => '' ), 5 => array( 'Vendor_ID' => 3, 'Quantity' => '' ), 6 => array( 'Vendor_ID' => 4, 'Quantity' => '' ), 7 => array( 'Vendor_ID' => 4, 'Quantity' => '' ), 8 => array( 'Vendor_ID' => 4, 'Quantity' => '' ) );

您不再需要$Tick，因为您可以使用Vendor_ID作为外部数组的键。

Answer 2

看起来解决此问题的最简单方法是首先聚合供应商数量，然后使用您正在使用的密钥构建最终数组。

我假设输入看起来像这样：

$_POST['product'] = [
    ['vendor_id' => 1, 'quantity' => 55],
    ['vendor_id' => 1, 'quantity' => 55],
    ['vendor_id' => 1, 'quantity' => 55],
    ['vendor_id' => 3, 'quantity' => null],
    ['vendor_id' => 3, 'quantity' => null],
    ['vendor_id' => 3, 'quantity' => null],
    ['vendor_id' => 4, 'quantity' => null],
    ['vendor_id' => 4, 'quantity' => null],
    ['vendor_id' => 4, 'quantity' => null],
];

汇总数量：

$aggregates = [];
foreach ($_POST['product'] as $product) {
    $id = $product['vendor_id'];
    if ( ! isset($aggregates[$id])) {
        $aggregates[$id] = [];
    }
    if ($product['quantity'] > 0) {
        $aggregates[$id][] = $product['quantity'];
    }
}

聚合数组现在应如下所示：

$aggregates = [
    1 => [
        0 => 55,
        1 => 55,
        2 => 55,
    ],
    3 => [], // Empty
    4 => [], // Empty
];

正如您所看到的，数据现在整齐有序，可以随心所欲地放入任何格式。使用您在问题中使用的键就可以了：

$output = [];
foreach ($aggregates as $vid => $qty) {
    $quantity = implode(',', $qty);
    $output[] = ['Vendor_ID' => $vid, 'Quantity' => $quantity];
}

输出现在应如下所示：

$output = [
    ['Vendor_ID' => 1, 'Quantity' => '55,55,55'],
    ['Vendor_ID' => 3, 'Quantity' => ''],
    ['Vendor_ID' => 4, 'Quantity' => ''],
];

Answer 3

虽然最后一个答案的输出（Sverri M. Olsen）更有用，但这将输出您正在寻找的内容。在这里，您将数量作为字符串获得，而使用Sverri的方法，您首先得到一个数组。

$Display_Arr = array();
$vendors=array();
foreach ($_POST['product'] AS $_1){

  if (!in_array($_1['vendor_id'],$vendors)){
    $vendors[]=$_1['vendor_id'];
    $Display_Arr[sizeof($vendors)-1] = array(
      "Vendor_ID" => $_1['vendor_id'],
      "Quantity" => $_1['quantity']
    );
  }
  else{
    $vendorKey=array_search($_1['vendor_id'],$vendors);
    $Display_Arr[$vendorKey]["Quantity"] .=(!empty($Display_Arr[$vendorKey]["Quantity"])?',':null).$_1['quantity'];
  }
}

合并以下数组

3 个答案: