我在下面的示例中有一个从数据库中提取的字符串。我正在尝试将字符串循环到HTML表格中以显示结果,如图中所示。字符串的长度可能不同,但始终采用相同的格式。
$string = "18/05-01/06 01/06-06/07 06/07-22/08 22/08-14/09 DR Record + 2 21.47 20.24 27.15 20.24 BE Record + 2 24.05 22.68"
_______________________________________________________________________
|18/05-01/06 | 01/06-06/07 | 06/07-22/08 | 22/08-14/09 |
_______________________________________________________________________
DR Record + 2 | 21.47 | 20.24 | 27.15 | 20.24 |
_______________________________________________________________________
BE Record + 2 | 24.05 | 22.68 | | |
_______________________________________________________________________
我尝试的所有东西似乎都不起作用。任何想法都将不胜感激。
这是我到目前为止所尝试的
$string = "18/05-01/06 01/06-06/07 06/07-22/08 22/08-14/09 DR Record + 2 21.47 20.24 27.15 20.24 BE Record + 2 24.05 22.68"
$parts = preg_split('/\s+/', $string );
$date = array();
$record = array();
$price = array();
foreach($parts as $part) {
// check date
if(strpos($part,'-') !== false) {
$date[] = $part;
}
// check price
elseif(strpos($part, '+') !== false) {
$record[] = $part;
}
// echeck record
elseif(strpos($part, '.') !== false) {
$price[] = $part;
}
}
答案 0 :(得分:1)
$parts = preg_split('/\s+/', $string ); //it returns an array
答案 1 :(得分:0)
<?php
function gsb($string, $start, $end)
{
$string = " " . $string;
$ini = strpos($string, $start);
if ($ini == 0)
return "";
$ini += strlen($start);
$len = strpos($string, $end, $ini) - $ini;
return substr($string, $ini, $len);
}
$s= "18/05-01/06 01/06-06/07 06/07-22/08 22/08-14/09 DR Record + 2 21.47 20.24 27.15 20.24 BE Record + 2 24.05 22.68";
$s1=explode(" ",gsb("*".$s,"*"," DR"));//'*' is just used to add an char at first so that we can extract string between it.
$dr=explode(" ",gsb($s," DR Record "," BE Record"));
$be=explode(" ",gsb($s.'*',$dr[count($dr)-2].' '.$dr[count($dr)-1].' ',"*"));//Edited according to comment and you need to access values from $be[2] as $be[0]$$be[1] will contain those two words.
?>
现在你有3个数组$s1
,$dr
&amp; $be
包含您需要的所有表值,现在只需根据您的要求使用它。