Question

我使用PHP代码中的SQL查询来显示网站上的数据库字段。有没有办法删除空（NULL）字段输出中的空格（空格）？

这是我的代码：

<?php 
    $sql = "SELECT * FROM dining ORDER BY date DESC LIMIT 0, 3";

    $dining = new Database($sql);
    while($dining->results()){

    echo "          
                    <span class='date'>". date("F jS, Y", strtotime($dining->date)) ."</span>
<h3>&nbsp;$dining->title</h3>
<h4>&nbsp;$dining->Comforts</h4> 
&nbsp;$dining->com1<br/>
&nbsp;$dining->com2<br/>
&nbsp;$dining->com3<br/>
&nbsp;$dining->com4<br/>
&nbsp;$dining->com5<br/>
&nbsp;$dining->com6<br/>
<h4>&nbsp;$dining->Breakers</h4>
&nbsp;$dining->break1<br/>
&nbsp;$dining->break2<br/>
<h4>&nbsp;$dining->Wild</h4>
&nbsp;$dining->wild1<br/>
&nbsp;$dining->wild2<br/>
<h4>&nbsp;$dining->Tureens</h4>
&nbsp;$dining->tur1<br/>
&nbsp;$dining->tur2<br/>
&nbsp;$dining->tur3<br/>
<h4>&nbsp;$dining->Desserts</h4>
&nbsp;$dining->des1<br/>
&nbsp;$dining->des2<br/>
&nbsp;$dining->des3<br/>
&nbsp;$dining->des4<br/><br/>
";  
}
?>

Answer 1

如果要抑制空白值，则必须单独测试每个值以决定是否应输出，例如

if (strlen($dining->des1) > 0) {
   echo "&nbsp;{$dining->des1}<br />";
}

Answer 2

if(isset(trim($dining->wild1)){
  echo "&nbsp;{$dining->wild1}<br />";
}

Answer 3

这可能符合法案：

<?php
while($dining->results())
{
    echo "<span class='date'>". date("F jS, Y", strtotime($dining->date)) ."</span>";

if( !empty( $dining->title ) ) echo "<h3>&nbsp;$dining->title</h3>";
if( !empty( $dining->Comforts ) ) echo "<h4>&nbsp;$dining->Comforts</h4> ";
if( !empty( $dining->com1 ) ) echo "&nbsp;$dining->com1<br/>";
if( !empty( $dining->com2 ) ) echo "&nbsp;$dining->com2<br/>";
if( !empty( $dining->com3 ) ) echo "&nbsp;$dining->com3<br/>";
if( !empty( $dining->com4 ) ) echo "&nbsp;$dining->com4<br/>";
if( !empty( $dining->com5 ) ) echo "&nbsp;$dining->com5<br/>";
if( !empty( $dining->com6 ) ) echo "&nbsp;$dining->com6<br/>";
if( !empty( $dining->Breakers ) ) echo "<h4>&nbsp;$dining->Breakers</h4>";
if( !empty( $dining->break1 ) ) echo "&nbsp;$dining->break1<br/>";
if( !empty( $dining->break2 ) ) echo "&nbsp;$dining->break2<br/>";
if( !empty( $dining->Wild ) ) echo "<h4>&nbsp;$dining->Wild</h4>";
if( !empty( $dining->wild1 ) ) echo "&nbsp;$dining->wild1<br/>";
if( !empty( $dining->wild2 ) ) echo "&nbsp;$dining->wild2<br/>";
if( !empty( $dining->Tureens ) ) echo "<h4>&nbsp;$dining->Tureens</h4>";
if( !empty( $dining->tur1 ) ) echo "&nbsp;$dining->tur1<br/>";
if( !empty( $dining->tur2 ) ) echo "&nbsp;$dining->tur2<br/>";
if( !empty( $dining->tur3 ) ) echo "&nbsp;$dining->tur3<br/>";
if( !empty( $dining->Desserts ) ) echo "<h4>&nbsp;$dining->Desserts</h4>";
if( !empty( $dining->des1 ) ) echo "&nbsp;$dining->des1<br/>";
if( !empty( $dining->des2 ) ) echo "&nbsp;$dining->des2<br/>";
if( !empty( $dining->des3 ) ) echo "&nbsp;$dining->des3<br/>";
if( !empty( $dining->des4 ) ) echo "&nbsp;$dining->des4<br/><br/>";

}
?>

当值为NULL或包含空字符串时，PHP的empty()将返回true。 More in the manual

不要显示空格

3 个答案: