Mysql Distinct select with replace

Question

我有以下mySql select语句，它返回以下结果，并争取得到我所追求的结果。

 select `tvshow`.`idShow` AS `idShow`,`tvshow`.`c00` AS `ShowName`,
         if(count(distinct `episode`.`c12`),
         count(distinct `episode`.`c12`),0) AS `TotalSeasons`,
        if(count(`episode`.`c12`),count(`episode`.`c12`),0) AS `TotalEpisodeCount`
    from
        ((((`tvshow`
        left join `tvshowlinkpath` ON ((`tvshowlinkpath`.`idShow` = `tvshow`.`idShow`)))
        left join `path` ON ((`path`.`idPath` = `tvshowlinkpath`.`idPath`)))
        left join `episode` ON ((`episode`.`idShow` = `tvshow`.`idShow`)))
        left join `files` ON ((`files`.`idFile` = `episode`.`idFile`)))
    group by `tvshow`.`idShow`
    having (count(`episode`.`c12`) > 0)

选择结果

我正试图获得第四列，其中列出了季节，例如“第1季，第2季，第3季”

我可以通过运行以下select

来获取所需的数据

select distinct c12 from episode where idShow = 1

返回以下内容。

所以我认为我可以使用替换来将结果更改为“Season1”但不知道如何让它只返回一个包含“Seasin1，Season2，Season3”的字符串，然后将其添加到选择语句中在视图的顶部并将它们组合在一起？

我想要的结果（使用Photoshop就可以了解这一点）

Answer 1

只需添加GROUP_CONCAT(episode.c12)作为附加列：

select `tvshow`.`idShow` AS `idShow`,`tvshow`.`c00` AS `ShowName`,
         if(count(distinct `episode`.`c12`),
         count(distinct `episode`.`c12`),0) AS `TotalSeasons`,
        if(count(`episode`.`c12`),count(`episode`.`c12`),0) AS `TotalEpisodeCount`,
        `GROUP_CONCAT(episode.c12)` as `Seasons`
    from
        ((((`tvshow`
        left join `tvshowlinkpath` ON ((`tvshowlinkpath`.`idShow` = `tvshow`.`idShow`)))
        left join `path` ON ((`path`.`idPath` = `tvshowlinkpath`.`idPath`)))
        left join `episode` ON ((`episode`.`idShow` = `tvshow`.`idShow`)))
        left join `files` ON ((`files`.`idFile` = `episode`.`idFile`)))
    group by `tvshow`.`idShow`
    having (count(`episode`.`c12`) > 0)

有关此MySQL特定功能的文档，请参阅http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat。