为什么预先声明std :: basic_string <t>制动boost :: regex？</t>

Question

使用Microsoft Visual Studio 2012编译器，使用boost 1.53，我有一些使用的工作代码：

#include <boost/regex.hpp>

后来我将以下两行添加到regex.hpp之前包含的头文件中：

namespace std {template<class T> class basic_string<T>;}
typedef std::basic_string<TCHAR> tstring;

现在我得到了一堆编译错误，但如果在这些其他行之前包含regex.hpp，则没有错误。

许多错误中的前几个是：

c:\program files (x86)\boost\boost_1_53\boost\regex\v4\instances.hpp(106): error C2027: use of undefined type 'std::basic_string<_Elem,_Traits,_Alloc>'
19>          with
19>          [
19>              _Elem=char16_t,
19>              _Traits=std::char_traits<unsigned short>,
19>              _Alloc=std::allocator<char16_t>
19>          ]
19>c:\program files (x86)\boost\boost_1_53\boost\regex\v4\instances.hpp(106): error C2065: 'const_iterator' : undeclared identifier
19>c:\program files (x86)\boost\boost_1_53\boost\regex\v4\instances.hpp(106): error C2923: 'boost::match_results' : 'const_iterator' is not a valid template type argument for parameter 'BidiIterator'
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364): error C2825: '_Iter': must be a class or namespace when followed by '::'
19>          c:\program files (x86)\boost\boost_1_53\boost\regex\v4\iterator_traits.hpp(116) : see reference to class template instantiation 'std::iterator_traits<_Iter>' being compiled
19>          with
19>          [
19>              _Iter=int
19>          ]
19>          c:\program files (x86)\boost\boost_1_53\boost\regex\v4\match_results.hpp(68) : see reference to class template instantiation 'boost::re_detail::regex_iterator_traits<T>' being compiled
19>          with
19>          [
19>              T=int
19>          ]
19>          c:\program files (x86)\boost\boost_1_53\boost\regex\v4\instances.hpp(106) : see reference to class template instantiation 'boost::match_results<BidiIterator>' being compiled
19>          with
19>          [
19>              BidiIterator=int
19>          ]
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364): error C2039: 'iterator_category' : is not a member of '`global namespace''
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364): error C2146: syntax error : missing ';' before identifier 'iterator_category'
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364): error C2602: 'std::iterator_traits<_Iter>::iterator_category' is not a member of a base class of 'std::iterator_traits<_Iter>'
19>          with
19>          [
19>              _Iter=int
19>          ]
19>          c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364) : see declaration of 'std::iterator_traits<_Iter>::iterator_category'
19>          with
19>          [
19>              _Iter=int
19>          ]
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(364): error C2868: 'std::iterator_traits<_Iter>::iterator_category' : illegal syntax for using-declaration; expected qualified-name
19>          with
19>          [
19>              _Iter=int
19>          ]
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(365): error C2825: '_Iter': must be a class or namespace when followed by '::'
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(365): error C2039: 'value_type' : is not a member of '`global namespace''
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(365): error C2146: syntax error : missing ';' before identifier 'value_type'
19>c:\program files (x86)\microsoft visual studio 11.0\vc\include\xutility(365): error C2602: 'std::iterator_traits<_Iter>::value_type' is not a member of a base class of 'std::iterator_traits<_Iter>'

请问有人告诉我我的std :: basic_string的预先说明有什么问题吗？

Answer 1

您已从声明中省略了几个模板参数。正确的看起来像：

template<class charT, class traits = char_traits<charT>,
         class Allocator = allocator<charT> >
class basic_string;

不要试图自己这样做。使用<string>。

Answer 2

  

请允许任何人告诉我我的std::basic_string预告片有什么问题吗？

它有三个模板参数：

template<class charT, class traits = char_traits<charT>,
    class Allocator = allocator<charT> >
class basic_string;

但是没有理由自己申报标准类型，正如你所证明的那样，没有理由不这样做。所以不要这样做;如果您需要声明，请包含标题。