我有以下.js代码但是当我测试网站时,它只显示每个但没有内容的文字。我想在最后实现的是能够显示5个帖子,并在底部添加一个链接以显示更多的帖子:
$(document).ready(function(){
url = 'http://hopexxx.com/category/daily-devotion/feed/';
$.ajax({
type: "GET",
url: document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=1000&callback=?&q=' + encodeURIComponent(url),
dataType: 'json',
error: function(){
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: function(data){
var postlist = data.responseData.feed.entries;
var html = '<ul data-role="listview" data-filter="true">';
for (var i = 0; i < 5; i++) {
html += '<li>';
html += '<a href="#">';
html += '<div class="entry">entry.title</div>';
html += '<div class="entry">author</div>';
html += '<div class="entry">publishedDate</div>';
html += '<div class="entry">contentSnippet</div>';
html += '</a>';
html += '</li>';
}
html += '</ul>';
$("#postlist").append(html);
$("#postlist ul[data-role=listview]").listview();
}});
});
答案 0 :(得分:0)
在data.responseData.feed.entries上尝试$ .each循环,有关详细信息,请参阅here
答案 1 :(得分:0)
如果你知道你的帖子列表不是空的,并且每个条目都有属性'title','author','publishedDate'和'contentSnippet'试试这个:
var postlist = data.responseData.feed.entries;
var html = '<ul data-role="listview" data-filter="true">';
for (var i = 0; i < 5; i++) {
var entry = postlist[i];
html += '<li>';
html += '<a href="#">';
html += '<div class="entry">' + entry.title + '</div>';
html += '<div class="entry">' + entry.author + '</div>';
html += '<div class="entry">' + entry.publishedDate + '</div>';
html += '<div class="entry">' + entry.contentSnippet + '</div>';
html += '</a>';
html += '</li>';
}
html += '</ul>';
$("#postlist").append(html);