我想将我的博客帖子结果显示为jQuery移动列表。目前所有的标题,日期,作者和片段都是逐行出现的,我希望能够点击每个帖子并直接以移动格式查看内容。这是我的代码:
$(document).ready((function(){
url = 'http://hopexxx.com/category/daily-devotion/feed/';
$.ajax({
type: "GET",
url: document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=1000&callback=?&q=' + encodeURIComponent(url),
dataType: 'json',
error: function(){
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: function(xml){
postlist = xml.responseData.feed.entries;
//console.log(postlist);
var data='<ul data-role="listview" data-filter="true">';
$.each(postlist, function(idx, data) {
$('#postlist').append('<div class="entry">' + data.title + '</div>');
$('#postlist').append('<div class="entry">' + data.author + '</div>');
$('#postlist').append('<div class="entry">' + data.publishedDate + '</div>');
$('#postlist').append('<div class="entry">' + data.contentSnippet + '</div>');
console.log(data);
'</ul>';
});
}
});
}));
html代码:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<script src="css/style.css"></script>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.css" />
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script src="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.js"></script>
<script src="js/script.js"></script>
</head>
<body>
<div id="blog" data-role="page">
<div data-role="header" class="sys_hd" data-position="fixed" data-id="sys_header" >
<h1>Sysads Posts</h1>
</div><!-- header -->
<div data-theme="c" data-role="content" id="postlist"> </div><!-- content -->
<div data-role="footer" data-position="fixed" data-id="sys_footer" >
<div data-role="navbar" >
<ul>
<li><a href="#blog" class="sys_ft">Home</a></li>
<li><a href="#blog" class="sys_ft">Disclaimer</a></li>
</ul>
</div><!-- navbar -->
</div><!-- footer -->
</div><!-- page -->
</body>
</html>
答案 0 :(得分:0)
试试这个......
$(document).ready(function(){
url = 'http://hopexxx.com/category/daily-devotion/feed/';
$.ajax({
type: "GET",
url: document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=1000&callback=?&q=' + encodeURIComponent(url),
dataType: 'json',
error: function(){
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: function(xml){
var postlist = xml.responseData.feed.entries;
var html = '<ul data-role="listview" data-filter="true">';
$.each(postlist, function(idx, data) {
html += '<li>';
html += '<a href="#">';
html += '<div class="entry">' + data.title + '</div>';
html += '<div class="entry">' + data.author + '</div>';
html += '<div class="entry">' + data.publishedDate + '</div>';
html += '<div class="entry">' + data.contentSnippet + '</div>';
html += '</a>';
html += '</li>';
});
html += '</ul>';
$("#postlist").append(html);
$("#postlist ul[data-role=listview]").listview();
});
});
});
我所做的就是将帖子包装在单个列表项中,也包含在链接标记中。我不知道链接的网址是什么(返回数据中的属性),所以我将其留作#
供您填写。
<强> Here's a working example... 强>