Question

protected void btndelete_Click(object sender, EventArgs e)
{
    DataTable dt = new DataTable();

    for (int i = 0; i < listview1.Items.Count; i++)
    {
        ListViewDataItem items = listview1.Items[i];
        CheckBox chkBox = (CheckBox)items.FindControl("chkdel");

        if (chkBox.Checked == true)
        {
            if (Session["CurrentTable"] != null)
            {
                dt = (DataTable)Session["CurrentTable"];
                dt.Rows.RemoveAt(i);
            }
        }
        else
        {
        }
    }

    Session["CurrentTable"] = dt;
    listview1.DataSource = dt;
    listview1.DataBind();
    BindDataToGridviewDropdownlist();     
}

这里只删除一行。如何删除listview中的多个已检查项？

Answer 1

正如Hans Derks在评论中所提到的那样，您每次都会从会话中获取数据表，但实际上并未使用Session["CurrentTable"]=dt;进行更新，例如：

protected void btndelete_Click(object sender, EventArgs e)
{
    DataTable dt = new DataTable();

    for (int i = 0; i < listview1.Items.Count; i++)
    {
        ListViewDataItem items = listview1.Items[i];
        CheckBox chkBox = (CheckBox)items.FindControl("chkdel");

        if (chkBox.Checked == true)
        {
            if (Session["CurrentTable"] != null)
            {
                dt = (DataTable)Session["CurrentTable"];
                dt.Rows.RemoveAt(i);
                Session["CurrentTable"]=dt;
                listview1.DataSource = dt;
                listview1.DataBind();
            }
        }
        else
        {
        }
    }

    BindDataToGridviewDropdownlist();     
}

Answer 2

Pranav答案的重构版本：

protected void btndelete_Click(object sender, EventArgs e)
{
    // Get the Table from the session.
    DataTable dt = (DataTable)Session["CurrentTable"];
    // Only actually proceed, if we have a value.
    if(dt != null)
    {
        // Loop through each item.
        for (int i = 0; i < listview1.Items.Count - 1; i++)
        {
            // Find the checkbox to determine if it's checked.
            ListViewDataItem items = listview1.Items[i];
            CheckBox chkBox = (CheckBox)items.FindControl("chkdel");
            if (chkBox.Checked == true)
            {
                // Remove the row at the current index.
                dt.rows.RemoveAt(i);
            }
        }
        // Update the session and rebind the data.
        Session["CurrentTable"] = dt;
        listview1.DataSource = dt;
        listview1.DataBind();
        BindDataToGridviewDropdownlist(); 
    }
}

Answer 3

这对我有用.....

protected void btndelete_Click(object sender, EventArgs e)
        {
            DataTable dt = new DataTable();
            if (Session["CurrentTable"] != null)
            {
                dt = (DataTable)Session["CurrentTable"];
                int j = 0;
                for (int i = 0; i < listview1.Items.Count; i++)
                {
                    ListViewDataItem items = listview1.Items[i];
                    CheckBox chkBox = (CheckBox)items.FindControl("chkdel");

                    if (chkBox.Checked == true)
                    {
                        dt.Rows.RemoveAt(j);
                        dt.AcceptChanges();
                    }
                    else
                    {
                        j++;
                    }
                }
                Session["CurrentTable"] = dt;
                listview1.DataSource = dt;
                listview1.DataBind();
                BindDataToGridviewDropdownlist();
            }
        }

如何删除ListView中的多个已检查项？

3 个答案: