Question

我一直在Symfony 2.3中使用基于cookbook recipie How To Handle File Uploads With Doctrine的附件实体。

即使在功能测试中也能很好地工作。然而，将它与Doctrine DataFixtures一起使用会给我带来麻烦。

[Symfony\Component\HttpFoundation\File\Exception\FileException] The file "o-rly-copy.jpg" was not uploaded due to an unknown error.

这没有帮助，但是我确实运行php app/console doctrine:fixtures:load -v来显示堆栈跟踪，看起来异常不会出现在持久化方法上，而是出现在$manager->flush()

上

Attachment::setFile()需要一个UploadedFile的实例，所以我想知道是否有一种方法。

似乎错误发生在Symfony\Component\HttpFoundation\File\UploadedFile

的第225行

return $this->test ? $isOk : $isOk && is_uploaded_file($this->getPathname())

is_uploaded_file()的条件返回false，因为该文件已在服务器上。

<?php

/**
 * Prepopulate the database with image attachments.
 */
final class AttachmentFixtures extends AbstractFixture implements OrderedFixtureInterface, ContainerAwareInterface
{
    private static $imageData = array(
        array(
            'name' => "O RLY?",
            'file' => "o-rly",
            'type' => "jpg",
        ),
        //...
    );

    public function getPathToImages()
    {
        return $this->container->get('kernel')->getRootDir() . '/../src/Acme/DemoBundle/Resources/public/default/images';
    }

    public function getPathToUploads()
    {
        return $this->container->get('kernel')->getRootDir() . '/../web/uploads/fixtures';
    }

    /**
     * {@inheritDoc}
     */
    public function load(ObjectManager $manager)
    {
        $imageReferences = array();
        $filesystem = $this->container->get('filesystem');

        foreach (self::$imageData as $image) {
            $imageFilename         = sprintf('%s.%s',      $image['file'], $image['type']);
            $copiedImageFilename   = sprintf('%s-copy.%s', $image['file'], $image['type']);

            $pathToImageFile = sprintf('%s/%s', $this->getPathToImages(), $imageFilename);

            try {
                $filesystem->copy($pathToImageFile, $pathToCopiedFile = sprintf('%s/%s', $this->getPathToUploads(), $copiedImageFilename));
                $filesystem->chmod($pathToCopiedFile, 0664);
            } catch (IOException $e) {
                $this->container->get('logger')->err("An error occurred while copying the file or changing permissions.");
            }

            $imageFile = new UploadedFile(
                $pathToCopiedFile,                                              // The full temporary path to the file
                $copiedImageFilename,                                           // The original file name
                'image/' . 'jpg' === $image['type'] ? 'jpeg' : $image['type'],  // Mime type - The type of the file as would be provided by PHP
                filesize($pathToCopiedFile),
                null,
                null,
                true
            );

            $imageAttachment = new Attachment();

            $imageAttachment->setName($image['name']);
            $imageAttachment->setFile($imageFile);

            // Populate a reference array for later use
            $imageReferences['attachment-'.$image['file']] = $imageAttachment;

            $manager->persist($imageAttachment);
        }

        $manager->flush(); // <-- Exception throw here


        // Create references for each image to be used by other entities that
        // maintain a relationship with that image.
        foreach ($imageReferences as $referenceName => $image) {
            $this->addReference($referenceName, $image);
        }
    }
}

Answer 1

现在有一个更好的解决方案：

UploadedFile的构造函数有一个布尔$test参数，该参数使用is_uploaded_file禁用检查。此参数已添加用于测试/夹具代码。

只需将其设置为true，isValid()的{{1}}检查就不再是问题了。

示例：

UploadedFile

Answer 2

Thanks to stof，解决方案是使Attachment::setFile()（或Document::setFile()，如果使用cookbook示例）提示UploadedFile的父类{{1}的实例在fixtures类中，创建一个新实例并将其传递给setFile方法

<强> Attachment.php

Symfony\Component\HttpFoundation\File\File

<强> AttachmentFixtures.php

<?php

namespace Acme\DemoBundle\Entity;

use Symfony\Component\HttpFoundation\File\File;
//...

class Attachment
{
    /**
     * Sets file.
     *
     * @param File $file
     */
    public function setFile(File $file = null)
    {
        $this->file = $file;
        // check if we have an old image path
        if (isset($this->path)) {
            // store the old name to delete after the update
            $this->temp = $this->path;
            $this->path = null;
        } else {
            $this->path = 'initial';
        }
    }

    //...
}

使用Doctrine DataFixtures时，Symfony HttpFoundation UploadedFile“因未知错误而未上传”

2 个答案: