Question

这是用户在其中输入数据的表单。

<form action="addemployee.php" method="POST" id="addEmployeeToDataBase">
  <input type="text" name="username" placeholder="UserName..." class="txtInput" required="" />
  <input type="text" name="fullname" placeholder="Full Name..." class="txtInput" required="" />
   <br />
  <input type="email" name="email" placeholder="Email Address..." class="txtInput" required="" />
  <input type="password" name="password" placeholder="Password..." class="txtInput" required="" />
   <br />
  <select name="dept" id="txtInput">
      <option value="-1">Select Department</option>
      <option value="Back-Office">Back-Office</option>
      <option value="HR">HR</option>
      <option value="Marketing">Marketing</option>
      <option value="Sales">Sales</option>
      <option value="Technical">Technical</option>
  </select>
     <br />
  <input type="text" name="address" placeholder="Address..." class="txtInput" required=""/>
  <input type="text" name="city" placeholder="City..." class="txtInput" required="" />
     <br />
  <input type="text" name="pincode" placeholder="Pin/Postal/Zip Code..." class="txtInput" required="" />
  <input type="text" name="country" placeholder="Country..." class="txtInput" required="" />
     <br />
  <p style="font-size: 17px;" />Date of Joining:<input type="date" name="joiningdate" placeholder="Joining Date" class="txtInput" required="" />
     <br />
  <input type="submit" name="submit" id="submit" value="Add Employee"/>

现在我想使用sql语句，输入的数据将同时发送到不同的表。

Table employee (emp_id, username, email, password, dept, address, city, pincode, country and joiningdate).

Table dept (dept_id, dept_name, dept_head, and emp_id).

此表单基本上插入到employee表中。

现在“问题”是我想分别将单一形式的数据插入到employee和dept表中，其中来自表单的dept的输入数据也应该插入到dept表的dept_name列中，并且还应该更新带有输入数据的dept表的emp_id。

请指导我。

Answer 1

$query1= "INSERT INTO employee ( username, email,...)
            VALUES ('".$_POST["username"]."', ...)";
        if($result1 = mysql_query($query1))
        {
            $emp_id = mysql_insert_id();

            $query2= "INSERT INTO dept ( emp_id, dept_name, ...)
            VALUES ('".$emp_id."', '".$_POST["dept_name"]."',...)";

            if($result2 = mysql_query($query2))
            {
                //success msg
            }
        }

Answer 2

首先使用mysql函数last_insert_id将数据插入到employee表中，您可以获取emp_id值并进入department表。

假设，emp_id是自动递增的值。

Answer 3

这可能会有所帮助（我正在使用Ubuntu 12.04和LAMP，它对我有用）

$sql1 = "INSERT INTO users_account_details (uname,email,pass1,pass2) 
VALUES('$_POST[uname]','$_POST[email]','$_POST[pass1]',DES_ENCRYPT('$_POST[pass2]'))";

$sql2 = "INSERT INTO users_personal_details (name,gender,dob,address,mobile) 
VALUES('$_POST[name]','$_POST[gender]','$dob','$_POST[address]','$_POST[mobile]')";

if (!mysqli_query($con,$sql1))
  {
  die('Error: ' . mysqli_error($con));
  }
if (!mysqli_query($con,$sql2))
  {
  die('Error: ' . mysqli_error($con));
 }

如何使用单一表单在2个不同的表中插入表单数据

3 个答案: