首先,这是一个我在Java 1课程中坚持的简单问题。这是一个静态的时间,我已经设置为8:49:12“今天”,我要弄清楚午夜过了多少秒,这到底是“到”午夜。 8小时49分12秒。 这是我现在的代码:
hour = 8;
minute = 59;
second = 32;
System.out.println("The static time used for this program was: " + hour + ":" + minute + ":" + second);
我的问题是,我不清楚如何从和获得时间,午夜。
所以基本上输出需要是:
Number of seconds since midnight:
Number of seconds to midnight:
之后的空间是秒。
谢谢,请解释原因,以及如何选择如何解决这个问题。我想学习:P
答案 0 :(得分:7)
试试这个简单的数学:
System.out.println("Number of seconds since midnight:" +(second + (minute*60) + (hour*3600)));
System.out.println("Number of seconds to midnight:" +((60-second) + ((60-1-minute)*60) + (24-1-hour)*3600));
答案 1 :(得分:3)
final static int SEC_IN_MIN = 60;
final static int SEC_IN_HOUR = SEC_IN_MIN * 60;
int secFromMidnight = hour * SEC_IN_HOUR + minute * SEC_IN_MIN + second;
int secToMidnight = (24 * SEC_IN_HOUR) - secFromMidnight;
答案 2 :(得分:3)
鉴于时间的特殊性,您可以简单地使用Calendar
API
Calendar fromMidnight = Calendar.getInstance();
fromMidnight.set(Calendar.HOUR, 0);
fromMidnight.set(Calendar.MINUTE, 0);
fromMidnight.set(Calendar.SECOND, 0);
fromMidnight.set(Calendar.MILLISECOND, 0);
Calendar toMidnight = Calendar.getInstance();
toMidnight.setTime(fromMidnight.getTime());
toMidnight.add(Calendar.DATE, 1);
System.out.println(fromMidnight.getTime());
System.out.println(toMidnight.getTime());
Calendar toFromTime = Calendar.getInstance();
toFromTime.set(Calendar.HOUR, 8);
toFromTime.set(Calendar.MINUTE, 59);
toFromTime.set(Calendar.SECOND, 32);
toFromTime.set(Calendar.MILLISECOND, 0);
long secondsFromMidnight = (toFromTime.getTimeInMillis() - fromMidnight.getTimeInMillis()) / 1000;
long secondsToMidnight = (toMidnight.getTimeInMillis() - toFromTime.getTimeInMillis()) / 1000;
System.out.println("from = " + secondsFromMidnight + "; to " + secondsToMidnight);
哪些输出......
from = 32372; to 54028
或者您可以使用JodaTime ...
MutableDateTime now = MutableDateTime.now();
now.setMillisOfDay(0);
now.setSecondOfDay(32);
now.setMinuteOfDay(59);
now.setHourOfDay(8);
DateTime fromMidnight = now.toDateTime().toDateMidnight().toDateTime();
DateTime toMidnight = fromMidnight.plusDays(1);
Duration duration = new Duration(fromMidnight, toMidnight);
Duration dFromMidnight = new Duration(fromMidnight, now);
System.out.println("From midnight: " + dFromMidnight.getStandardSeconds());
Duration dToMidnight = new Duration(now, toMidnight);
System.out.println("To Midnight: " + dToMidnight.getStandardSeconds());
哪些输出......
From midnight: 32372
To Midnight: 54028
答案 3 :(得分:3)
JAVA
中有一个名为TimeUnit
的枚举,可以将时间转换为这样的任何时间单位:
int hour = 8;
int minute = 59;
int second = 32;
System.out.println("The static time used for this program was: " + hour + ":" + minute + ":" + second);
long secInMidnight = TimeUnit.HOURS.toSeconds(24);
long timeInSeconds = (TimeUnit.HOURS.toSeconds(8) + TimeUnit.MINUTES.toSeconds(minute) + second);
System.out.println("\nSince midnight: " + timeInSeconds + "\nUntil midnight: " + (secInMidnight - timeInSeconds) );
答案 4 :(得分:1)
由于问题的数学简单性,@ Vimal Bera的公认答案很好并且完全足够。但是如果您仍然喜欢“正式化”(由库支持)方法而不进行“大量”计算,那么您可以在 Java-8 中执行此操作:
LocalTime time = LocalTime.of(8, 59, 32);
System.out.println(
"Seconds since midnight: "
+ time.get(ChronoField.SECOND_OF_DAY)); // 32372
System.out.println(
"Seconds to midnight: "
+ (86400 - time.get(ChronoField.SECOND_OF_DAY))); // 54028
答案 5 :(得分:0)
你的答案是在java.util.Calendar类中。请参阅get()/ set()方法: http://docs.oracle.com/javase/6/docs/api/java/util/Calendar.html
答案 6 :(得分:0)
import java.util.Calendar;
public class HelloWorld{
public static void main(String []args){
int hour = 8;
int minute = 59;
int second = 32;
System.out.println("The static time used for this program was: " + hour + ":" + minute + ":" + second);
final Calendar currentTime = Calendar.getInstance();
currentTime.set(2013,Calendar.SEPTEMBER,24,8,59,32);
final Calendar midNight = Calendar.getInstance();
midNight.clear();
midNight.set(2013, Calendar.SEPTEMBER, 25);
System.out.println(.001*(midNight.getTimeInMillis() - currentTime.getTimeInMillis()));
}
}
考虑使用Calendar
和/或尝试JodaTime
库