在单链表上插入方法,这有用吗?

时间:2013-09-24 05:11:17

标签: java list methods linked-list insertion

我更关心我正在处理的插入方法,一个单独链接列表,最多只需要10个节点。我有一个SinglyLinkedList,其getScore()方法会返回得分。我附带相关方法来查看流程。基本上我想要完成的事情和我在插入方法上所做的事情将节点(有一个分数)插入到左边的正确分类位置是最高分,最右边是最低分。如果我有[100]--[80]--[65]并且另一个得分为67的节点出现,只要大小小于10,[100]--[80]--[67]--[65]就会变为if (size == 10),这意味着列表已满并且任何其他节点出现in只会将它与最后一个节点进行比较,例如95的新节点只与65进行比较,如果它大于65则表示95必须在列表中的某个位置,删除最后一个节点'65'并迭代通过找到合适的地方95.如果另一个节点例如高于100,例如200 ..那么只要[200]--[100]--[95]--[80]--[67]它就会size < 10,否则会得到最低分,所以列表会仍然保持10个节点。你明白了。

public void insert(Node n) { 
  //insert if node's score is higher than the last node
  int currScore = n.getScore();
  Node pos = head;

  if(pos.getScore() < currScore) {
    addFirst(n);
  }

  if(pos != null) {
    if(getSize() == 10) {
      if(tail.getScore() < currScore) {
        removeLast();
      } else { 
        n = null;
      }
    } else {
      while(getSize() < 10) {
        if((pos.getNext() != null) && (pos.getNext().getScore() > currScore))
          pos.setNext(pos);
      }
      insertAfter(n,pos);
    }
  }
}

public void addFirst(Node v) {
  if(head == null) {
    head = v;
    tail = v;
    size++;
}

public void insertAfter(Node p, Node v) { //insert v after p
  Node t = p.getNext();
  p.setNext(v);
  v.setNext(t);
  size++;
}

public void removeLast() {
  if(head == null) {
    return;
  }
  Node pos = head;
  if(pos.getNext() == null) {
    pos = null;
  }
  Node curr = head.getNext();
  while(curr.getNext() != null) {
    pos = curr;
    curr.setNext(curr);

    if(curr.getNext() == null) {
      curr = null;
    }
  }         
}

public class Node  {
    private String name;
    private int score;
    private Node next;

    public Node() {
        name = "";
        score = 0;
        next = null;
    }

public Node(String name, int score, Node next) {
    this.name = name;
    this.score = score;
    this.next = next;
}
public String getName() {
    return name;
}

public int getScore() {
        return score;
}

public Node getNext() {
        return next;
}
public void setName(String name) {
        this.name = name;
}

public void setScore(int score) {
        this.score = score;
}

public void setNext(Node next) {
    this.next = next;
}
}

public class SinglyLinkedList {
    public Node head;
    public Node tail;
    public int size;
    static final int MAXSIZE = 10;

public SinglyLinkedList() {
    head = null;
    tail = null;
    size = 0;
}
public void addFirst(Node v) {
    if(head == null) {
    head = v;
    tail = v;
    size++;
    }
}
public void addLast(Node v) {
    v.setNext(null);
    tail.setNext(v);
    tail = v;
    size++;
}
public void insertAfter(Node p, Node v) { //insert v after p
    Node t = p.getNext();
    p.setNext(v);
    v.setNext(t);
    size++;
}
public void removeFirst() {
   if(head == null) {
       return;
   }
   Node t = head;
   head.setNext(head);
   t = null;
   size--;
}
public void removeLast() {
    if(head == null) {
        return;
    }
    Node pos = head;
    if(pos.getNext() == null) {
        pos = null;
    }
    Node curr = head.getNext();
    while(curr.getNext() != null) {
        pos = curr;
        curr.setNext(curr);

        if(curr.getNext() == null) {
            curr = null;
        }
    }         
}

public void insert(Node n) { //insert if node's score is higher than the last node
    int currScore = n.getScore();
    Node pos = head;

    if(pos.getScore() < currScore) {
            addFirst(n);
     }

    if(pos != null) {
        if(getSize() == 10) {
            if(tail.getScore() < currScore) {
                removeLast();
            } else { 
                n = null;
            }
        } else {
            while(getSize() <= 10) {
                if(pos.getNext() != null && pos.getNext().getScore() > currScore)
                pos.setNext(pos);
            }
            insertAfter(n,pos);
        }
    }
}
public int getSize() {
    return size;
}
}

1 个答案:

答案 0 :(得分:0)

你的setNext()方法在哪里?你在setNext()中增加大小吗? ..我认为你的程序会无限循环,因为 -

 while(getSize() < 10) {
                if(pos.getNext() != null && pos.getNext().getScore() > currScore)
                pos.setNext(pos);
            }

你在哪里做大小++ ??

实施您正在使用的所有方法......