在python中解压缩对象变量

时间:2013-09-24 04:16:19

标签: python class variables iterable-unpacking

我在想是否有办法解包对象属性。 通常这样做涉及一系列:

self.x = x
self.y = y
... #etc.

然而,应该可以做得更好。

我正在考虑类似的事情:

def __init__(self,x,y,z):
  self.(x,y,z) = x,y,z

或者也许:

用x,y,z解包(自我)

甚至功能如下:

def __init__(self,x,y,z):
  unpack(self,x,y,z)

有什么想法吗?还是有更多的pythonic方法来做到这一点?

3 个答案:

答案 0 :(得分:3)

您可能希望使用namedtuple,这完全符合您的要求:

官方Python文档中的代码示例

Point = namedtuple('Point', ['x', 'y'], verbose=True)

以上代码相当于:

class Point(tuple):
    'Point(x, y)'

    __slots__ = ()

    _fields = ('x', 'y')

    def __new__(_cls, x, y):
        'Create a new instance of Point(x, y)'
        return _tuple.__new__(_cls, (x, y))

    @classmethod
    def _make(cls, iterable, new=tuple.__new__, len=len):
        'Make a new Point object from a sequence or iterable'
        result = new(cls, iterable)
        if len(result) != 2:
            raise TypeError('Expected 2 arguments, got %d' % len(result))
        return result

    def __repr__(self):
        'Return a nicely formatted representation string'
        return 'Point(x=%r, y=%r)' % self

    def _asdict(self):
        'Return a new OrderedDict which maps field names to their values'
        return OrderedDict(zip(self._fields, self))

    def _replace(_self, **kwds):
        'Return a new Point object replacing specified fields with new values'
        result = _self._make(map(kwds.pop, ('x', 'y'), _self))
        if kwds:
            raise ValueError('Got unexpected field names: %r' % kwds.keys())
        return result

    def __getnewargs__(self):
        'Return self as a plain tuple.   Used by copy and pickle.'
        return tuple(self)

    __dict__ = _property(_asdict)

    def __getstate__(self):
        'Exclude the OrderedDict from pickling'
        pass

    x = _property(_itemgetter(0), doc='Alias for field number 0')

    y = _property(_itemgetter(1), doc='Alias for field number 1')

以下是如何使用它:

>>> p = Point(11, y=22)     # instantiate with positional or keyword arguments
>>> p[0] + p[1]             # indexable like the plain tuple (11, 22)
33
>>> x, y = p                # unpack like a regular tuple
>>> x, y
(11, 22)
>>> p.x + p.y               # fields also accessible by name
33
>>> p                       # readable __repr__ with a name=value style
Point(x=11, y=22)

<强>来源: http://docs.python.org/2/library/collections.html#namedtuple-factory-function-for-tuples-with-named-fields

值得一提的是namedtuple只是一个普通的类,你可以创建一个继承它的类。

答案 1 :(得分:0)

定义像unpack(self,x,y,z)这样的函数可能不是一个好主意,因为函数不够通用(对象的组成在运行时定义)

这里解释了基于属性名称实例化变量的更通用的方法 http://code.activestate.com/recipes/286185-automatically-initializing-instance-variables-from/

答案 2 :(得分:0)

我很确定你可以这样做:     self.x,self.y,self.z = x,y,z