通过MySQL查询获取Wordpress用户显示名称的帖子

时间:2013-09-23 18:26:34

标签: php mysql wordpress

我在Wordpress中有一个搜索表单,用于搜索自定义帖子类型中的所有帖子标题,内容和自定义字段。但它不会被作者搜索。我希望搜索关键字与显示名称匹配,然后输出该作者的任何帖子。

这是我当前的代码(display_name的一部分显然是错误的,但说明了我想要完成的事情)。一切都有效,除了display_name部分的get帖子。任何帮助或指导表示赞赏:)

// Code originally modified 
// from http://www.deluxeblogtips.com/2012/04/search-all-custom-fields.html

global $wpdb;
// Gets the ?crs= search from the submitted form
$keyword = sanitize_text_field( $_GET['crs'] );
$keyword = '%' . like_escape( $keyword ) . '%'; 

// Search in all custom fields
$post_ids_meta = $wpdb->get_col( $wpdb->prepare( "
    SELECT DISTINCT post_id FROM {$wpdb->postmeta}
    WHERE meta_value LIKE '%s'
", $keyword ) );

// Search in post_title and post_content
$post_ids_post = $wpdb->get_col( $wpdb->prepare( "
    SELECT DISTINCT ID FROM {$wpdb->posts}
    WHERE post_title LIKE '%s'
    OR post_content LIKE '%s'
", $keyword, $keyword ) );

// Search in User Table for Display Name
// This is where I'm not sure what how to get the posts by display_name
$post_ids_user = $wpdb->get_col( $wpdb->prepare( "
    SELECT DISTINCT post_id FROM {$wpdb->users}
    WHERE display_name LIKE '%s'
", $keyword ) );

$post_ids = array_merge( $post_ids_meta, $post_ids_post, $post_ids_user );

// Query arguments for WP_Query
$args = array(
    'post_type'   => 'courses',
    'post_status' => 'publish',
    'limit' => '',
    'post__in'    => $post_ids,
);

1 个答案:

答案 0 :(得分:2)

有一件事我想建议而不是运行多个查询加入你的表并一起工作

  

SELECT DISTINCT post_id FROM {$ wpdb-> users}       WHERE display_name LIKE'%s'这是错误的查询,你无法从users表中获取post id,帖子和用户的关系在posts表中保留,每个帖子都包含post_author列中的用户ID

试试这个

$post_ids = $wpdb->get_col( $wpdb->prepare( "
    SELECT p.ID FROM $wpdb->posts p
INNER JOIN $wpdb->users u ON (p.`post_author` = u.`ID`)
LEFT JOIN $wpdb->postmeta m ON (p.`ID`= m.`post_id`)
WHERE ( u.display_name LIKE '%s' OR p.post_title LIKE '%s' 
OR p.post_content LIKE '%s' OR m.meta_value LIKE '%s')
GROUP BY p.`ID`
", $keyword ) );

//print_r($post_ids); //you will get the post ids
$post_ids=array_values(array_unique($post_ids));