Question

早上好，

我想创建一个继承自列表的类，例如我可以做的：

import pickle

object_list = []

object_list.append(an_object)
object_list.append(an_other_object)

object_list.dump('/home/user/my_file')

或

import pickle

[an_objet, an_other_object].dump('/home/user/my_file')

我不知道如何创建我的课程，

感谢您阅读

Answer 1

我明白了

import pickle

class my_list(list):
  def__init___(self, *args)
    list.__init__(self, *args)

  def dumps(self, path):
    with open(path, 'wb') as f:
      pick = pickle.Pickler(f)
      pick.dump(self)

  def load(self, path):
    with open(path, 'rb') as f:
      pick = pickle.Unpickler(f)
      for i in pick.load():
        self.append(i)

Python覆盖对象列表

1 个答案: