Question

我想点击Popup（Label）时显示LabelShift_MouseDown。我基本上想要在点击标签时编辑移位（一个标签一个班次），但我想点击标签以显示弹出窗口（使用编辑按钮编辑弹出窗口）。那么有人可以告诉我该怎么做，因为这段代码不起作用。这是我的代码：

<ItemsControl ItemsSource="{Binding Path=ScheduleItem}" Tag="{Binding .}" Margin="0,10,0,0">
   <ItemsControl.ItemsPanel>
      <ItemsPanelTemplate>
         <Canvas IsItemsHost="True" />
      </ItemsPanelTemplate>
   </ItemsControl.ItemsPanel>
   <ItemsControl.ItemContainerStyle>
      <Style TargetType="{x:Type ContentPresenter}">
         <Setter Property="Canvas.Left" Value="{Binding Path=Start, Converter={StaticResource timeToPositionConverter}}" />
         <Setter Property="Canvas.Top" Value="{Binding Path=Index}" />
      </Style>
   </ItemsControl.ItemContainerStyle>
   <ItemsControl.ItemTemplate>
      <DataTemplate DataType="TimeLineEntry">
         <Label Width="{Binding Duration}" Height="20" Tag="{Binding .}" BorderThickness="1" BorderBrush="DarkGray" MouseDown="LabelShift_MouseDown">
            <Label.Background>
               <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
                  <GradientStop Color="#FF3B4DFF" Offset="0.996" />
                  <GradientStop Color="#FF6674F8" Offset="0" />
                  <GradientStop Color="#FFC7CEFF" Offset="0.791" />
               </LinearGradientBrush>
            </Label.Background>
            <Popup>
               <StackPanel>
                  <TextBox Text="Text" />
                  <Button Content="Update" />
                  <Button Content="Delete" Style="{StaticResource DeleteButton}"/>
               </StackPanel>
            </Popup>
         </Label>
      </DataTemplate>
   </ItemsControl.ItemTemplate>
</ItemsControl>

private void LabelShift_MouseDown(object sender, MouseButtonEventArgs e)
{
   Popup p = (sender as Label).Content as Popup;
   p.StaysOpen = true;
}

Answer 1

您无需在Popup内定义DataTemplate。将其添加到窗口的Resources或用户控件中，如

       <Popup x:Key="myPopup">
           <StackPanel>
              <TextBox Text="Text" />
              <Button Content="Update" />
              <Button Content="Delete" Style="{StaticResource DeleteButton}"/>
           </StackPanel>
        </Popup>

在MouseDown处理程序中只需执行：

      Popup popup = Resources["myPopup"] as Popup;
      popup.PlacementTarget = sender as UIElement;;
      popup.IsOpen = true

Answer 2

尝试使用p.IsOpen = true;代替p.StaysOpen = true;。

如何在ItemsControl中显示弹出窗口

2 个答案: