Question

休息-server.xml中：

<jaxrs:server id="baseApi" address="http://localhost:8080/myfashions/catalog">
    <jaxrs:serviceBeans>
        <bean class="com.myfashions.api.service.rest.implementation.CatalogServiceImpl"/>
    </jaxrs:serviceBeans>
    <jaxrs:providers>
        <ref bean="customRequestHandler"/>
        <ref bean="customResponseHandler"/>
        <ref bean="restExceptionMapper"/>
        <bean class="org.codehaus.jackson.jaxrs.JacksonJaxbJsonProvider"/>
    </jaxrs:providers>
</jaxrs:server>

接口：

public interface CatalogService {

    @Path("/categories")
    @GET
    @Produces({MediaType.APPLICATION_JSON})
    SelectCategoryBeanList getMyfashionCategories();
}

类别：

@Service
@Path("/myfashions/catalog")
public class CatalogServiceImpl implements CatalogService {
    @Override
    public SelectCategoryBeanList getMyfashionCategories() {
        ...
        ...
    }
}

当我调用http://localhost:8080/myfashions/catalog/categories时，我找不到根资源匹配请求路径/myfashions/catalog/categories，相对路径：/categories异常。任何人都可以帮助我。

Answer 1

地址构造如下：

http(s)://<host>:<port>/<webapp>/<servlet URL-pattern>/<jaxrs:server address>/<resources>

您的地址设置不正确。

假设你的web上下文是myApp，而你的servlet url-pattern是/ rest / *，来完成

http://localhost:8080/myApp/rest/myfashions/catalog/categories

你需要：

webapp name = myApp
servlet url-pattern = /rest/*
jaxrs:server address = myfashions
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

我通常只在版本控制时在jaxrs：server元素上设置一个地址，或者当我因任何原因实际需要多个休息服务器时。大多数时候我将地址设置为“”。

编辑：或者，如果你想：

http://localhost:8080/myfashions/catalog/categories

你需要：

webapp name = myfashions
servlet url-pattern = /*
jaxrs:server address = ""
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

JAX-RS的注释继承无效

1 个答案: