Python中的闰年计划

Question

我很难对代码进行故障排除。我所要做的就是让用户进入开始和结束的一年，然后能够计算两者之间的所有闰年。我仍然是Python的新手，并且无法弄清楚为什么我的while循环没有做我想做的事情。

starting = int(raw_input('Enter starting year: '))
ending = int(raw_input('Enter ending year: '))
print 'Leap years between', starting, 'and', ending
while starting <= ending:
    if starting % 4 == 0 and starting % 100 != 0:
       print starting
    if starting % 100 == 0 and starting % 400 == 0:
       print starting
    starting = starting + 1

这就是我现在所拥有的。我真的不希望没有给我答案，但如果我能得到一些暗示为什么我的while循环不起作用我会非常感激。

这是我在IDE中看到的输出：

Answer 1

代码工作得很好。这是以下会议：

Enter starting year: 2008
Enter ending year: 2032
Leap years between 2008 and 2032
2008
2012
2016
2020
2024
2028
2032

这完全符合information give her e。

控制台会话：

>>> from leapyear import leap
>>> leap()
Enter starting year: >? 2008
Enter ending year: >? 2032
Leap years between 2008 and 2032
2008
2012
2016
2020
2024
2028
2032

leapyear.py

def leap():
    starting = int(raw_input('Enter starting year: '))
    ending = int(raw_input('Enter ending year: '))

    print 'Leap years between', starting, 'and', ending
    while starting <= ending:
        if starting % 4 == 0 and starting % 100 != 0:
            print(starting)
        if starting % 100 == 0 and starting % 400 == 0:
            print(starting)
        starting += 1

您也可以使用列表推导来执行此功能：

def new_leap(start, end):
    return [x for x in xrange(start, end + 1)
            if (x % 400 == 0) or (x % 4 == 0 and not x % 100 == 0)]

控制台会话：

>>> from leapyear import new_leap
>>> new_leap(2008, 2032)
[2008, 2012, 2016, 2020, 2024, 2028, 2032]

Answer 2

我认为其中将包含所有测试用例

我们在value = c中添加了所有无效案例 并刚匹配并从b

中删除了该值

indexPath(for cell:)

Answer 3

def is_leap(year):
    leap = False

    if year%4 ==0 :
        leap = True

    elif year%100 ==0:
        leap = False

    elif year%400 ==0:
        leap = True

    return leap


year = int(raw_input())
print is_leap(year)