Java - 将线扫描成构造函数

时间:2013-09-23 03:04:48

标签: java constructor java.util.scanner

我已经被困在这个家庭作业上一段时间了。基本上我必须为读取文件的日期创建一个构造函数,该文件由每行上的一个日期组成。每个日期都应存储在Date对象中。

但是,我必须在阅读之后打印出日期,如“日期:1997年6月17日”,类似于“System.out.println(date);”。

所以我遇到的问题是能够正确地遍历每一行。我有一个while循环,它将扫描文本文件中的所有行,但只有完成后才能访问最后一行。我如何对其进行编码,以便我可以按顺序一次访问每一行?

对于您感兴趣的人,这是assignment.

到目前为止,这是我的代码,如果我在解释我正在尝试做什么时不够清楚,我很抱歉。我是新手。

public class Date {

private int month; // 1-12
private int monthNum; // number of month
private int day; // 1-31 varies by month
private int year; // any year
private String chkMonth, chkDay;
private String theMonth;
private int theYear,valid;

/**
 * days in each month with 0 at the index since there is no month "zero"
 */
private static final int[] daysPerMonth = { 0, 31, 28, 31, 30, 31, 30, 31,
        31, 30, 31, 30, 31 };

/**
 * constructor: call checkMonth to confirm proper value for month; call
 * checkDay to confirm proper value for day
 * 
 * @param theMonth
 *            the month of the year
 * @param theDay
 *            the day of the month
 * @param theYear
 *            the year
 */

public Date() {
    Scanner in = null;
    try {
        in = new Scanner(new File("dates.txt"));
    } catch (FileNotFoundException exception) {
        System.err.println("failed to open dates.txt");
        System.exit(1);
    }

    while (in.hasNextLine()) {
        theMonth = in.next();
        chkMonth = theMonth.replaceAll("\\.", "");
        chkMonth = chkMonth.toLowerCase();
        chkDay = in.next();
        chkDay = chkDay.replaceAll("\\,", "");
        day = Integer.parseInt(chkDay);
        theYear = in.nextInt();
        // need more code for DateRange objects
        valid = 1;
        year = theYear; // could validate year
        if (checkMonth(chkMonth) == 0)
            valid = 0; // validate month

        if ((checkDay(day)) == 0)
            valid = 0; // validate day

        System.out.println(this);

    }

}



/**
 * utility method to confirm proper month value
 * 
 * @param theMonth
 * @return testMonth or throw an IllegalArgumentException
 */
private int checkMonth(String theMonth) {
    if (((theMonth.compareTo("jan")) == 0)
            || ((theMonth.compareTo("january")) == 0))
        monthNum = 1;
    else if (((theMonth.compareTo("feb")) == 0)
            || ((theMonth.compareTo("february")) == 0))
        monthNum = 2;
    else if (((theMonth.compareTo("mar")) == 0)
            || ((theMonth.compareTo("march")) == 0))
        monthNum = 3;
    else if (((theMonth.compareTo("apr")) == 0)
            || ((theMonth.compareTo("april")) == 0))
        monthNum = 4;
    else if (((theMonth.compareTo("may")) == 0))
        monthNum = 5;
    else if (((theMonth.compareTo("june")) == 0))
        monthNum = 6;
    else if (((theMonth.compareTo("july")) == 0))
        monthNum = 7;
    else if (((theMonth.compareTo("aug")) == 0)
            || ((theMonth.compareTo("august")) == 0))
        monthNum = 8;
    else if (((theMonth.compareTo("sept")) == 0)
            || ((theMonth.compareTo("september")) == 0))
        monthNum = 9;
    else if (((theMonth.compareTo("oct")) == 0)
            || ((theMonth.compareTo("october")) == 0))
        monthNum = 10;
    else if (((theMonth.compareTo("nov")) == 0)
            || ((theMonth.compareTo("november")) == 0))
        monthNum = 11;
    else if (((theMonth.compareTo("dec")) == 0)
            || ((theMonth.compareTo("december")) == 0))
        monthNum = 12;

    if (monthNum > 0 && monthNum <= 12) // validate month
        return monthNum;
    else
        return monthNum = 0;
    /*
     * else // month is invalid throw new
     * IllegalArgumentException("month must be 1-12");
     */
}

/**
 * utility method to confirm proper day value based on month and year
 * 
 * @param testDay
 * @return testDay or throw an IllegalArgumentException
 */
private int checkDay(int testDay) {
    // check if day in range for month
    if (testDay > 0 && testDay <= daysPerMonth[monthNum])
        return testDay;

    // check for leap year
    if (monthNum == 2 && testDay == 29
            && (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)))
        return testDay;

    // System.out.println("Invalid Date");

    return 0;

}

/**
 * return a String of the form month/day/year
 * 
 * @return a String of the form month/day/year
 */
public String toString() {
    if (valid == 1) {
        String ret = "Date: ";
        ret += theMonth + " ";
        ret += day + ", ";
        ret += year;
        return ret;
    } else
        return "Date Invalid";

}

}

1 个答案:

答案 0 :(得分:0)

处理文件的代码应该在Date类中,但在 Lab3 类中。而且,你的Date构造函数应该有参数,如下所示:

public Date(theMonth, theDay, theYear) {
    this.year = theYear;
    this.month = theMonth;
    this.day = theDay;
}

然后在您的Lab3课程中,您可以通过执行以下操作来创建新的Date对象:

Date nextDate = new Date(in.next(), in.next(), in.nextInt());

当然,你需要做更多的错误检查。

它还有助于存储您在某处创建的所有Date对象,例如在ArrayList中。