Question

int s;

number2=input.next();

for (int i=0;i<number2.length();i++){ 

    s=(int)(number2.charAt(i));

    while ((s<48)||(s>57)){
    System.out.println("Enter the amount");
    number2=input.next();
    s=number2.charAt(i);    
     }

}

使用此代码我只能生成一个整数。如果我想生成带小数的double，我该怎么做？

Answer 1

您可以尝试使用Integer.parseInt或Double.parseDouble来解析整数字符串或双精度值。

Answer 2

你可以作弊......

String text = "123";
boolean isDouble = false;
boolean isInt = false;
try {
    Double.parseDouble(text);
    try {
        Integer.parseInt(text);
        isInt = true;
    } catch (NumberFormatException exp) {
        isDouble = true;
    }

    System.out.println("isInt = " + isInt);
    System.out.println("isDouble = " + isDouble);
} catch (NumberFormatException exp) {
    System.out.println(text + " is not a valid number");
}

A123输出A123 is not a valid number ...

123输出......

isInt = true
isDouble = false

123.321输出......

isInt = false
isDouble = true

Answer 3

假设您正在阅读用户的输入，您可以使用nextInt()：

Scanner scan = new Scanner(System.in);
int n = 0;
try{
    n = scan.nextInt();
}
catch(NumberFormatException e){
    //do here what you want to do in case it's not an int
}

如果输入不是int，请不要忘记使用try / catch（同样适用于Juned的答案！）。

关于检查字符串是否为数字

3 个答案: