在字符串中第二次出现空格后删除文本

Question

我希望在Java中第二次出现空格后删除文本。不应使用正则表达式。

输入：

String S1 = "VOLKSWAGEN OF SANLEANDRO";
String S2 = "Stack Overflow Site";
String S3 = "Java Learning"; -- there is only one space

输出：

VOLKSWAGEN OF
Stack Overflow
Java Learning // as there is no second space entire string should be displayed

Answer 1

indexOf(" ");以及indexOf(" ", firstSpaceIndex);和substring(0, end)会这样做，有关详细信息，请参阅String API文档

Answer 2

你可以尝试

String s = "Hello world good bye";
s = s.replaceFirst(" (.*?) .*", " $1");
System.out.println(s);

打印

Hello world