Question

我使用array_uniqe删除数组（列表＃1）中的dupliactes，但是如何重新计算它的输出（列表＃2）的kyes到[0-x]（列表＃3）：

列表＃1：

 array (size=24)
          0 => string '2013-09-18' (length=10)
          1 => string '2013-09-18' (length=10)
          2 => string '2013-09-18' (length=10)
          3 => string '2013-09-18' (length=10)
          4 => string '2013-09-19' (length=10)
          5 => string '2013-09-19' (length=10)
          6 => string '2013-09-19' (length=10)
          7 => string '2013-09-19' (length=10)
          8 => string '2013-09-19' (length=10)
          9 => string '2013-09-19' (length=10)
          10 => string '2013-09-19' (length=10)
          11 => string '2013-09-20' (length=10)
          12 => string '2013-09-20' (length=10)
          13 => string '2013-09-20' (length=10)
          14 => string '2013-09-20' (length=10)
          15 => string '2013-09-21' (length=10)
          16 => string '2013-09-21' (length=10)
          17 => string '2013-09-21' (length=10)
          18 => string '2013-09-21' (length=10)
          19 => string '2013-09-21' (length=10)
          20 => string '2013-09-21' (length=10)
          21 => string '2013-09-22' (length=10)
          22 => string '2013-09-22' (length=10)
          23 => string '2013-09-22' (length=10)

列表＃2：

array (size=5)
  0 => string '2013-09-18' (length=10)
  4 => string '2013-09-19' (length=10)
  11 => string '2013-09-20' (length=10)
  15 => string '2013-09-21' (length=10)
  21 => string '2013-09-22' (length=10)

列表＃3：

array (size=5)
  0 => string '2013-09-18' (length=10)
  1 => string '2013-09-19' (length=10)
  2 => string '2013-09-20' (length=10)
  3 => string '2013-09-21' (length=10)
  4 => string '2013-09-22' (length=10)

Answer 1

$list3 = array_values($list2);

在PHP中使用array_unique后重新计算键的方法

1 个答案: