Question

我想创建一个函数来判断url中的数字是奇数还是偶数。这是关于法官的代码：

#!/usr/bin/env python
#-*- coding:utf-8 -*-

from django.http import HttpResponse,Http404
import datetime

def judge(reqest, number):
    try:
        number = int(number)
    except ValueError:
        raise Http404() 
    if number % 2 == 0:
        html = "<html><body>%d is even!</body></html>" % (number)
    else:
        html = "<html><body>%d is odd!</body></html>" % (number)
    return HttpResponse(html)

现在，我陷入了url.py，我不知道这样的编辑是否有效：

from django.conf.urls.defaults import *
from views import *

urlpatterns = patterns('',
   #(r'^$', time_now),
   (r'^number/(.+)$', judge), # we just want the number in the url, not more or less
)

但我也想处理空输入，但每次尝试时页面都会显示"Nothing input"：

def judge(reqest, number):
    if number is None:
        html = "nothing input!"
        return HttpResponse(html)
    try:
        number = int(number)
    except ValueError:
        raise Http404() 
    if number % 2 == 0:
        html = "<html><body>%d is even!</body></html>" % (number)
    else:
        html = "<html><body>%d is odd!</body></html>" % (number)
    return HttpResponse(html)

我该如何解决这个问题？

Answer 1

定义两个这样的网址

urls.py

from views import *

urlpatterns = patterns('',
   #(r'^$', time_now),
   (r'^number/(.+)/$', judge),
   (r'^number/$', judge),
)

设置默认值

views.py

def judge(reqest, number=None):
    ...

Django来配置一个包含数字的url

1 个答案: