Question

我正在尝试解析来自url的文本内容。这是代码：

<?php
$url = 'http://stackoverflow.com/questions/12097352/how-can-i-parse-dynamic-content-from-a-web-page';
$content = file_get_contents($url);
echo $content;                          // This parse everything on the page, including image + everything

$text=escapeshellarg(strip_tags($content));
echo "</br>";
echo $text;   // This gives source code also, not only the text content over page
?>

我想只获得在页面上写的文字。没有页面源代码。对此有何看法？我已经谷歌搜索了，但上面的方法只出现在各处。

Answer 1

您可以使用DOMDocument和DOMNode

$doc = new DOMDocument();
$doc->loadHTMLFile($url);
$xpath = new DOMXPath($doc);
foreach($xpath->query("//script") as $script) {
    $script->parentNode->removeChild($script);
}
$textContent = $doc->textContent; //inherited from DOMNode

您也可以这样做：

，而不是使用xpath

$doc = new DOMDocument();
$doc->loadHTMLFile($url); // Load the HTML
foreach($doc->getElementsByTagName('script') as $script) { // for all scripts
    $script->parentNode->removeChild($script); // remove script and content 
                                               // so it will not appear in text
}
$textContent = $doc->textContent; //inherited from DOMNode, get the text.

Answer 2

$content = file_get_contents(strip_tags($url));

这将删除页面中的HTML标记

Answer 3

要删除html标记，请使用：

$text = strip_tags($text);

Answer 4

简单的 cURL 将解决此问题。的 [TESTED]

<?php $ch = curl_init("http://stackoverflow.com/questions/12097352/how-can-i-parse-dynamic-content-from-a-web-page"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); //Sorry forgot to add this echo strip_tags(curl_exec($ch)); curl_close($ch); ?>

仅解析来自网址的文本内容

4 个答案: