获取参数的选择框出错

时间:2013-09-22 06:55:36

标签: ruby-on-rails ruby ruby-on-rails-2

我使用2个条件

使用2个选择框创建了一个搜索
  • ejecutives的选择框
  • 我的行政状态的选择框

当选择STATE = 0时,我的错误没有得到值

但是当我选择STATE = 1正在工作时

我的桌子

 TABLE EJECUTIVES
       |id|  |name| |lastname1|
 TABLE POLICIES
       |id|  |num_police|  |ejecutive_id| |state|

  state=  '0' is ok
          '1' is canceled
          '2' is expired

这是我的控制器

class PolicyManagement::PolicyController < ApplicationController

   def generate_print_ejecutive_comercial

     @ejecutives = Ejecutive.find(:all)
     @selected_ejecutive = Ejecutive.find_by_id(params[:search])  if params[:search]
     @selected_state = Policy.find_by_state(params[:state])  if params[:state]
     @search = Policy.find(:all,:conditions =>['ejecutive_id = ? AND state = ? ', @selected_ejecutive, @selected_state  ]   )
     @policies = @search.paginate( :page => params[:page], :per_page =>10)

   end

end

我的模特

class Policy < ActiveRecord::Base
   unloadable
   belongs_to :ejecutive
   has_many :policy
end

class Ejecutive < ActiveRecord::Base
  has_many :policies
end

这是我的看法,但对此并不了解

 <% form_tag :controller=>"policy_management/policy",:action=>"generate_print_ejecutive_comercial" do %>

 Ejecutives: 
<%= select_tag "search",options_for_select(@ejecutives.collect {|t| [t.name.to_s+" "+t.lastname1.to_s,t.id]}, params[:search].to_i ) %>

Status:
<%= select_tag "state", options_for_select([ ["Ok",0],["Cancel",1],["ok but not cancel",2]],params[:state].to_i) %>

<%= submit_tag "search", :name => nil %>
<% end %>

Results
<% @policies.each do |policy| %>
     <p> <%= policy.num_policy%> </p>
     <p> <%= policy.ejecutive.name %> </p>
     <p> <%= policy.ejecutive.last_name %> </p>
<% end %>
<%= will_paginate @policies %>

我尝试了这个,但只是取消状态(1),这实际上正在工作

<%= select_tag "state", options_for_select([ ["Ok",0],["Cancel",1],["ok but not cancel",2]],params[:state].to_i) %>

仅工作当我选择一个连续并且状态“1”=取消时显示此

  Ejecutive Load (0.2ms)  SELECT * FROM `ejecutives` 
  Ejecutive Columns (1.7ms)   SHOW FIELDS FROM `ejecutives`
  Ejecutive Load (0.6ms)   SELECT * FROM `ejecutives` WHERE (`ejecutives`.`id` = '5') LIMIT 1
  Policy Columns (2.8ms)   SHOW FIELDS FROM `policies`
  Policy Load (0.7ms)   SELECT * FROM `policies` WHERE (`policies`.`state` = '1') LIMIT 1
  Policy Load (29.9ms)   SELECT * FROM `policies` WHERE (ejecutive_id = 5 AND state = 1 ) 

但是当我选择一个连续并且状态确定(0)时,这不起作用并显示此

  Ejecutive Load (0.2ms)   SELECT * FROM `ejecutives` 
  Ejecutive Columns (1.5ms)   SHOW FIELDS FROM `ejecutives`
  Ejecutive Load (0.1ms)   SELECT * FROM `ejecutives` WHERE (`ejecutives`.`id` = '5') LIMIT 1
  Policy Columns (1.1ms)   SHOW FIELDS FROM `policies`
  Policy Load (0.3ms)   SELECT * FROM `policies` WHERE (`policies`.`state` = '0') LIMIT 1
  Policy Load (8.8ms)   SELECT * FROM `policies` WHERE (ejecutive_id = 5 AND state = 4 ) 

我不知道为什么这样做:SELECT * FROM policies WHERE(ejecutive_id = 5 AND state = 4)当我选择状态ok(0)

当我选择一个永久性和状态已过期(2)时,这不起作用并显示此

  Ejecutive Load (0.3ms)   SELECT * FROM `ejecutives` 
  Ejecutive Columns (1.5ms)   SHOW FIELDS FROM `ejecutives`
  Ejecutive Load (0.3ms)   SELECT * FROM `ejecutives` WHERE (`ejecutives`.`id` = '5') LIMIT 1
  Policy Columns (2.8ms)   SHOW FIELDS FROM `policies`
  Policy Load (6.4ms)   SELECT * FROM `policies` WHERE (`policies`.`state` = '2') LIMIT 1
  Policy Load (6.8ms)   SELECT * FROM `policies` WHERE (ejecutive_id = 5 AND state = 1098 ) 

我不知道为什么这样做:SELECT * FROM policies WHERE(ejecutive_id = 5 AND state = 1098)当我选择状态已过期时(2)

我将非常感谢所有的帮助

1 个答案:

答案 0 :(得分:1)

我认为你的逻辑错误和state = 1只是因为id == 1的政策有state = 1

看看这个:

Policy Load (6.4ms) SELECT * FROM `policies` WHERE (`policies`.`state` = '2') LIMIT 1
Policy Load (6.8ms) SELECT * FROM `policies` WHERE (ejecutive_id = 5 AND state = 1098 ) 

在第二个查询中,您正在搜索包含state = 1098的政策,因为您传递的是@selected_state policy模型实例的值。

尝试将您的行更改为:

 @search = Policy.find(:all,:conditions =>['ejecutive_id = ? AND state = ? ', @selected_ejecutive, params[:state]  ])