Question

public boolean isThereLetter(String name) {
        char[] chars = name.toCharArray();

        for (char c : chars) {
            if(!Character.isLetter(c)) {
                return false;
            }
        }

        return true;
    }

我这样调用了这个函数;

if(isThereLetter("Wdasdsa<>")){
        Log.d(TAG, "there is a letter");
    }else
        Log.d(TAG,"there isn't any letter");

但我注意到因为“＆lt;”这个char in ...（“Wdasdsa＆lt;＆gt;”）函数返回false。我该如何解决？

Answer 1

你的条件倒退了。如果字符串中的所有字符都是字母，则当前实现返回true。如果字符串中的任何字符是一个字母，那么听起来就像想要的返回true。

public boolean isThereLetter(String name) {
    char[] chars = name.toCharArray();

    for (char c : chars) {
        if(Character.isLetter(c)) {
            return true;
        }
    }

    return false;
}

Answer 2

当你遇到至少一个角色时，立即返回true说该角色找到了。更改代码如图所示

public boolean isThereLetter(String name) {
    char[] chars = name.toCharArray();

    for (char c : chars) {
        if(Character.isLetter(c)) {
            //You came across atleat one character.
            return true;
        }
    }

    //Never reached into the if block. No any character found
    return false;
}

有信吗？返回错误的值

2 个答案: