我不确定为什么我在以下SQL查询中收到语法错误。
查询的目标(以及稍后列出的架构/创建的视图)是查找经理的名称和公司名称,这些经理的收入超过所有经理的平均工资。< / p>
这是我写的查询及其附带的错误:
select ManagerLastname, MFirstName, MMidInitial, company_name
from ManagerInfo, Works
(select avg(salary) as AverageManagerSalary, Lastname
from Works,
group by Lastname) Work1
where ManagerInfo.ManagerLastname = Work1.Lastname and
Works.salary > Work1.AverageManagerSalary;
ORA-00933: SQL command not properly ended : select ManagerLastname, MFirstName, MMidInitial, company_name from ManagerInfo, Works (select avg(salary) as AverageManagerSalary, Lastname from Works, group by Lastname) Work1 where ManagerInfo.ManagerLastname = Work1.Lastname and Works.salary > Work1.AverageManagerSalary
我不确定此查询中语法错误的位置。我认为所有括号和“标点符号”都是正确的所以我认为这是嵌套 select 语句的问题,但我不确定在该语句中需要更改的内容......
以下是我的数据库的整体架构。这个模式以及我创建的上面视图“正确编译”,所以我知道错误与查询代码本身有关。
create table Employee(
Lastname varchar(10),
FirstName varchar(10),
MidInitial char(1),
gender char(1),
street varchar(10),
city varchar(10),
primary key(Lastname, FirstName, MidInitial));
create table company(
company_name varchar(20),
city varchar(10),
primary key(company_name));
create table Works(
Lastname varchar(10),
FirstName varchar(10),
MidInitial char(1),
company_name varchar(20),
salary numeric(8,2),
primary key(Lastname, FirstName, MidInitial, company_name),
foreign key(Lastname, FirstName, MidInitial) references Employee,
foreign key(company_name) references company);
create table Manages(
Lastname varchar(10),
FirstName varchar(10),
MidInitial char(1),
ManagerLastname varchar(10),
MFirstName varchar(10),
MMidInitial char(1),
start_date date,
primary key(Lastname, FirstName, MidInitial, ManagerLastname, MFirstName, MMidInitial),
foreign key(Lastname, FirstName, MidInitial) references Employee);
create view ManagerInfo as
(select distinct ManagerLastname, MFirstName, MMidInitial, street, city
from Manages, Employee
where Manages.ManagerLastname = Employee.Lastname and
Manages.MFirstName = Employee.FirstName and
Manages.MMidInitial = Employee.MidInitial);
顺便说一下,我正在使用SQL for Oracle 11g R2。
感谢您提供的任何帮助;非常感谢。
答案 0 :(得分:1)
在from子句中的Works之后缺少逗号? (第一个)然后在您的子选择中的Works之后似乎有一个额外的逗号。