c - const char *和char * casting(ADPCM解码)

时间:2013-09-22 02:03:45

标签: c char const exc-bad-access short

这是Objective-c姐妹问题,可能会提供一些见解: c and objective-c -- const char* and char*

我正在做以下事情:

g_ADPCMstate.valprev=32767;
g_ADPCMstate.index=0;


const char *modulatedBytes1 = {0xca,0x82,0x00,0x00,0x80,0x80,0x80,0x80};
char *modulatedBytes =  (char *)modulatedBytes1;
unsigned int moduleatedLength = 8;
short *decompressedBytes = NULL;

adpcm_decoder(modulatedBytes, decompressedBytes, moduleatedLength, &g_ADPCMstate);

函数声明是:

void      
adpcm_decoder(indata, outdata, len, state)      
    char indata[];      
    short outdata[];      
    int len;      
    struct adpcm_state *state; 

g_ADPCMstate是adpcm_state结构的全局实例变量。 http://codepad.org/5vyd0CXA是完整代码。当*outp++ = valprev;发生时函数崩溃,我从调试器得到一个BAD ACCESS语句。 outp是指向outData的指针,而valprev是一个long。

问题必须在于我对指针的理解,modulatedBytes和/或decompressedBytes

我对C和较低级别的概念知之甚少。我希望能够深入了解我的问题。

1 个答案:

答案 0 :(得分:2)

您将short *decompressedBytes = NULL;作为outdata参数传递给adpcm_decoder(),然后尝试取消引用它。你忘了分配decompressedBytes吗?