Question

我在java中制作检查器，当我点击GUI时，“New Game”按钮消失了。当我将鼠标悬停在鼠标上时会重新出现，但如果单击GUI，它将再次消失。你知道我做错了什么/我做错了吗？

public void setFrame()
    {
        boardSize  = 10;
        squareSize = 50;
        int imageSize = boardSize * squareSize;       
        image = new BufferedImage(imageSize, imageSize, BufferedImage.TYPE_INT_ARGB);
        imageIcon = new ImageIcon(image);
        jLabel = new JLabel(imageIcon);
        button = new JButton("New Game");
        button.setFocusable(false);
        button.setBounds(375, 5, 100, 20);
        pnl = new JPanel();
        pnl.setBounds(400, 10, 200, 100);
        pnl.setLayout(null);
        pnl.add(button);

        jFrame = new JFrame("Checker Board");
        jFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        jFrame.add(jLabel, BorderLayout.CENTER);
        jFrame.add(pnl);
        jFrame.setSize(506, 558);
        jFrame.setResizable(false);
        jFrame.setLocationRelativeTo(null);
        jFrame.setVisible(true);

        jFrame.validate();
    }

    /**
     * Paint the checker board onto the Image.
     */
    public void paint()
    {
        Graphics graphics = jFrame.getGraphics();

        pnl.paint(graphics);
        button.paint(graphics);

        graphics.setColor(Color.black);
        Font font = new Font("Score", Font.BOLD, 20);
        graphics.setFont(font);
        graphics.drawString("Score: ", 150, 47);
        graphics.drawString("Turn: ", 20, 47);
        graphics.setFont(font.deriveFont(0, 16.0F));
        graphics.drawString("Red: " + Game.score.getScoreRed() + "    Black: " + Game.score.getScoreBlack(), 230, 47);
        graphics.drawString((Game.redTurn ? "Red" : "Black"), 80, 47);

        // paint a red  board
        graphics.setColor(Color.red);
        graphics.fillRect(xShift, zShift, boardSize * squareSize, boardSize * squareSize);

        // paint the black squares
        graphics.setColor(Color.black);
        for (int row = 0; row < boardSize; row++)
        {
            for (int col = row % 2; col < boardSize; col += 2)
            {
                graphics.fillRect( row * squareSize + xShift, col * squareSize + zShift, squareSize, squareSize );
            }
        }

        for(int i = 0; i < 10; i++)
        {
            for(int j = 0; j < 10; j++)
            {
                if(Game.board.pieces[i][j] != null)
                {
                    Color pieceColor = Game.board.pieces[i][j].getColor().equals(EnumTeam.BLACK) ? Color.gray : Color.pink;
                    graphics.setColor(pieceColor);
                    graphics.fillOval((i * 50) + 10 + xShift, (j * 50) + 10 + zShift, 30, 30);
                    if(Game.board.pieces[i][j].isKing())
                    {
                        pieceColor = Game.board.pieces[i][j].getColor().equals(EnumTeam.BLACK) ? Color.darkGray : Color.magenta;
                        graphics.setColor(pieceColor);
                        graphics.fillOval((i * 50) + 20 + xShift, (j * 50) + 20 + zShift, 10, 10);
                    }
                }
            }
        }

        graphics.setColor(Color.cyan);
        drawRect(graphics, Game.board.getSelectedX(), Game.board.getSelectedZ(), 5);
    }

Answer 1

不要，永远使用Graphics graphics = jFrame.getGraphics();（或getGraphics一般）！这不是自定义绘画在Swing中完成的方式。事实上，你随后清除了图形上下文是你的核心问题。

所有绘画都应该在绘画API的上下文中完成，最好是从paintComponent扩展的任何组件覆盖JComponent（我个人更喜欢JPanel）

创建一个自定义组件并使用它来执行自定义绘制。与框架上的其他组件一起布局。

设置Performing Custom Painting和Painting in AWT and Swing以获取有关绘画如何在Swing中工作的更多详细信息。

MouseListener并不适合用作按钮，更好的选择是使用考虑鼠标点击和键盘事件的ActionListener ...

有关详细信息，请参阅How to write an Action Listener和How to use buttons

单击GUI时，JButton消失

1 个答案: