Question

MS-access查询：按名称和年龄分组，获取没有重复数据的详细信息（姓名和年龄）请在下面找到详细信息

表架构：

id: integer
name: varchar(100)
age: integer
city: varchar(100)

表中的

记录：

------------------------------------
id| name    | age | city
------------------------------------
1 | ram     | 25 | bhopal
2 | brajesh | 30 | indore
3 | ram     | 25 | indore
4 | ram     | 26 | bhopal
5 | ram     | 27 | mumbai
6 | brajesh | 30 | mumbai
7 | brajesh | 26 | dehli
------------------------------------

预期结果：

------------------------------------
name    | age | city | city
------------------------------------
ram     | 25 | bhopal | indore
brajesh | 30 | indore | mumbai
------------------------------------

预期输出的其他格式：

预期结果：

------------------------------------
name    | age | city
------------------------------------
ram     | 25 | bhopal, indore
brajesh | 30 | indore, mumbai
------------------------------------

Answer 1

这样可以解决问题：

select distinct d1.name, d1.age, concat(d1.city, ' , ' ,d2.city) AS city  from
Details d1 join Details d2
on d1.name = d2.name
and d1.age = d2.age
and d1.city != d2.city
and d1.id < d2.id

以下是SQLFiddle

另请注意，为此， ID必须是唯一的。

Answer 2

不幸的是，由于需要为每个不同的城市生成列，因此无法通过查询获得第一个输出。

这是如何在ms-access中获取第二个变体，但它不是最佳的：定义功能

public function SitiesOf(Name as String,Age as long) as String
    dim rst as recordset
    SitiesOf = ", "
    set rst = currentdb.Openrecordset("SELECT [city] FROM [Table] WHERE [name]='" & Name & "' AND [age]=" & Age & ";")
    while not rs.eof
        SitiesOf = SitiesOf & rst![city] & ", "
        rst.MoveNext
    wend
    rst.close
    set rst=Nothing
    SitiesOf = left(SitiesOf , len(SitiesOf)-2)
end function

撰写查询

SELECT [name] , [age] , SitiesOf([name],[age]) FROM [Table] GROUP BY [name] , [age]

查询以获取记录而不重复

2 个答案: