Question

我创建了一个“建议朋友”的PHP脚本，类似于facebook。我的数据库有2个表，用户（user_id，姓名，个人资料）和朋友（friends_id，user_one，user_two）。我的代码如下：

<?php

//----- gets all friends of my friends -------

$friends_of_friends = mysql_query(" SELECT u.*
        FROM (SELECT DISTINCT user_one as user_id
            FROM friends
            WHERE user_two IN (SELECT user_one as user_id
                         FROM friends
                     WHERE user_two = '$session_user_id'
                     UNION DISTINCT
                     SELECT user_two
                     FROM friends
                     WHERE user_one = '$session_user_id'
                       )
            UNION DISTINCT
            SELECT DISTINCT user_two
            FROM friends
            WHERE user_one IN (SELECT user_one as user_id
                     FROM friends
                     WHERE user_two = '$session_user_id'
                     UNION DISTINCT
                     SELECT user_two
                         FROM friends
                     WHERE user_one = '$session_user_id'
                       )
           ) f
          JOIN users u
          ON u.user_id = f.user_id  ");

while ($run_friends= mysql_fetch_assoc($friends_of_friends)) {
    $friend_friend_id = $run_friends['user_id'];


 // ---- gets friends of my friends that are not my friends -------------------------------

 $check_friend_query = mysql_query("  SELECT friends_id from friends WHERE  (user_one='$session_user_id' AND user_two='$friend_friend_id') OR (user_one='$friend_friend_id' AND user_two='$session_user_id')   ");

   if (mysql_num_rows($check_friend_query) != 1){ 

    $not_friends = mysql_query("SELECT `user_id`, `name`, `surname`, `email`, `profile` FROM `users` WHERE (`user_id`='$friend_friend_id' AND `user_id`!='$session_user_id')  ");

       while ($run_not_friends= mysql_fetch_assoc($not_friends)) {
         $not_friend_id = $run_not_friends['user_id'];
                 echo $not_friend_id;
       } //end while

   } //end if

} //end while

?>

我的代码工作得很好，并且把我想要的朋友的所有朋友都给了我。是否可以将所有上述代码组合在一个spl语句中？知道怎么做吗？

Answer 1

您的查询对于您要实现的目标来说似乎非常复杂。据我所知，与原始查询相关的唯一字段是user_one中的user_two和friends以及user_id中的users。通过使用子查询，查询的运行时将以exponanti的方式增加。

这意味着你可以将它重写为以下查询，这应该快得多，因为mysql可以缩短很多结果而不必每个子查询。它返回来自某个用户的朋友的朋友，我将从此处称为“x”。不是朋友的朋友的'x'的朋友不会被退回，并且由于最后的AND，它也不会返回用户。

SELECT DISTINCT c.* FROM friends as a, friends as b, users as c
WHERE (a.user_one = 1 AND (
  (a.user_two = b.user_one AND b.user_two = c.user_id) OR
  (a.user_two = b.user_two AND b.user_one = c.user_id)
  ) OR (a.user_two = 1 AND (
  (a.user_one = b.user_one AND b.user_two = c.user_id) OR
  (a.user_one = b.user_two AND b.user_one = c.user_id)
  )
 )) AND c.user_id != 1
ORDER BY c.`user_id` ASC

要从结果中删除所有来自“x”的直接朋友的用户，您可以使用NOT IN( ... )。我使用了一个子查询，因为我不相信没有子查询就有办法做到这一点。我本可以加入一个额外的friends表，但即使我测试当前用户是否是来自c.user_id的朋友对着新加入的表，查询也可以通过匹配其中任何其他朋友来进行查询的一部分，这是我们不想要的。子查询将（或应该）每个唯一的朋友从朋友执行一次。我认为如果您将这些查询分开并将两个返回的数组相互比较，性能会更好，但这不允许您在查询中使用LIMIT。

SELECT DISTINCT c.* FROM friends as a, friends as b, users as c
WHERE (a.user_one = 1 AND (
  (a.user_two = b.user_one AND b.user_two = c.user_id) OR
  (a.user_two = b.user_two AND b.user_one = c.user_id)
  ) OR (a.user_two = 1 AND (
  (a.user_one = b.user_one AND b.user_two = c.user_id) OR
  (a.user_one = b.user_two AND b.user_one = c.user_id)
  )
 )) AND c.user_id != 1 AND
 c.user_id NOT IN (
   SELECT friends.user_two FROM friends WHERE friends.user_one = 1 UNION
   SELECT friends.user_one FROM friends WHERE friends.user_two = 1
 )
ORDER BY c.`user_id` ASC

我相信这应该链接到正确的sqlfiddle：http://sqlfiddle.com/#!2/6c14e/2

在一个sql语句中结合我的php代码和mysql语句

1 个答案: