Question

package com.example.app123;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

public class MainActivity extends Activity {

    EditText input;
    EditText output;
    Button one;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        input = (EditText) findViewById(R.id.editText1);
        output = (EditText) findViewById(R.id.editText2);
        one = (Button) findViewById(R.id.button1);
        one.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                if (v == one) {
                    Context context1 = getApplicationContext();
                    CharSequence text1 = "Please enter a valid number";
                    int duration = Toast.LENGTH_SHORT;
                    final Toast toast = Toast.makeText(context1, text1,
                            duration);
                    toast.show();
                    int inputValue = Integer.parseInt(input.getText()
                            .toString());
                    int value = inputValue * inputValue;
                    output.setText(value);
                }
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it ispresent.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }
}

Answer 1

如果（v == one）仅使用此按钮，则在按钮单击代码中删除此条件

        input=(EditText)findViewById(R.id.editText1);
    output = (EditText) findViewById(R.id.editText2);
    one = (Button) findViewById(R.id.button1);
    one.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

                Context context1 = getApplicationContext();
                CharSequence text1 = "Please enter a valid number";
                int duration = Toast.LENGTH_SHORT;
                final Toast toast = Toast.makeText(context1, text1,
                        duration);
                toast.show();
                int inputValue = Integer.parseInt(input.getText()
                        .toString());
                int value = inputValue * inputValue;
                output.setText(value);

        }
    });

我希望它为你工作。

Answer 2

如果您有多个按钮：

Button b1=(Button)findviewById(R.id.b1);
Button b2=(Button)findviewById(R.id.b2);
one.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            switch(v.getid())
            case R.id.b1:
                CharSequence text1 = "Please enter a valid number";
                int duration = Toast.LENGTH_SHORT;
                final Toast toast = Toast.makeText(YourActivity.this, text1,
                        duration);
                toast.show();
                int inputValue = Integer.parseInt(input.getText()
                        .toString());
                int value = inputValue * inputValue;
                output.setText(value);
            break;
            case R.id.b1:
            break;
        }
    });

如何在android代码中删除强制关闭错误

2 个答案: