Question

我使用PIL打开图像以提取几个位并将它们写入字符串。应该是，该代码将除了具有（R <= 1＆amp; G＆lt; = 1＆amp;＆amp; B＆lt; = 1）并且取每种颜色的最后一位的代码。问题是它不起作用。

from PIL import Image
def extract_bits(color, bitmask):
    bitmask_len = len(bin(bitmask)[2:])
    extracted_bits = bin(color & bitmask)[2:]
    extracted_bits = '0' * (bitmask_len - len(extracted_bits)) + extracted_bits

    return extracted_bits

if __name__ == '__main__':
    img = Image.open('IMG_0707png')
    pixels = list(img.getdata())

    bits = ''
    for i in range(0, len(pixels), 1):
        r = pixels[i][0]
        g = pixels[i][1]
        b = pixels[i][2]

        if not (r <= 1 and g <= 1 and b <= 1): continue

        bits += extract_bits(r, 0x1)
        bits += extract_bits(g, 0x1)
        bits += extract_bits(b, 0x1)

    bits += '0' * (8 - len(bits) % 8)

    text = ''
    for i in range(0, len(bits), 8):
        text += chr(int(bits[i:i+8], 2))
    print text

我环顾了这个问题，发现在我的情况下不起作用的解决方案。 img = Image.open(open('IMG_0707.png', 'rb')) 在这两种情况下，我都会

File "<stdin>, line 1, in <module>"
File "<string>" line11, im <module>
File "c:\python27\lib\site-packages\PIL\Image.py", line 1980, in open
raise IOError("cannot identify image file")
IOError: cannot identify image file

此外，我试图指定确切的路径而没有运气。

img = Image.open(open("IMG_0707.png", 'rb'))
img = Image.open(open("c:\python27\IMG_0707.png", 'rb'))
img = Image.open(open("c:/python27/IMG_0707.png", 'rb'))

等等。我将不胜感激任何帮助。 Image, im trying to open

Answer 1

PNG已损坏。以下是ImageMagick所说的内容：

$ convert IMG_0707.png IMG_0707-new.png 
convert: IHDR: CRC error `IMG_0707.png' @ error/png.c/MagickPNGErrorHandler/1309.
convert: corrupt image `IMG_0707.png' @ error/png.c/ReadPNGImage/3294.
convert: missing an image filename `IMG_0707-new.png' @ error/convert.c/ConvertImageCommand/3011.

Answer 2

import Image
try:
    from StringIO import StringIO
except ImportError:
    from io import StringIO
import numpy as np

im = Image.open(StringIO(raw_data))

嗨，我有同样的问题，这是解决方案 raw_data：在我的情况下，它是base64解码的png文件

PIL image.open（）不能用于我的.png

2 个答案: