我有两个表帐户和余额
/---------------------\
| cid | name | mobile |
|---------------------|
| 1 | ABC | 12345 |
|---------------------|
| 2 | XYZ | 98475 |
\---------------------/
/----------------------------\
| date | cid | balance |
|----------------------------|
| 2013-09-19 | 1 | 5000 |
|----------------------------|
| 2013-09-19 | 2 | 7000 |
|----------------------------|
| 2013-09-20 | 1 | 300 |
|----------------------------|
| 2013-09-20 | 2 | 4500 |
|----------------------------|
| 2013-09-21 | 2 | 600 |
\----------------------------/
我想加入这两张表,并获得特定cid的最大日期余额。
输出结果为 -
/--------------------------------------------\
| cid | name | mobile | date | balance |
|--------------------------------------------|
| 1 | ABC | 12345 | 2013-09-20 | 300 |
|--------------------------------------------|
| 2 | XYZ | 98475 | 2013-09-21 | 600 |
\--------------------------------------------/
答案 0 :(得分:11)
您需要使用两个子查询:
SELECT a.cid, a.name, a.mobile, b.date, b.balance
FROM account a
JOIN
(
SELECT b1.* FROM balance b1
JOIN
(
SELECT cid, MAX(Date) As maxDate
FROM balance
GROUP BY cid
) b2
ON b1.cid = b2.cid
AND b1.date = b2.maxDate
) b
ON a.cid = b.cid;
输出:
| CID | NAME | MOBILE | DATE | BALANCE |
|-----|------|--------|----------------------------------|---------|
| 1 | ABC | 12345 | September, 20 2013 00:00:00+0000 | 300 |
| 2 | XYZ | 98475 | September, 21 2013 00:00:00+0000 | 600 |
答案 1 :(得分:1)
SELECT a.cid, a.name, a.mobile, MAX(b.date), b.balance
FROM account AS a
INNER JOIN balance AS b
WHERE a.cid=b.cid
GROUP BY cid;
抱歉,我没有注意到第3张表格中的余额列。
SELECT a.cid, a.name, a.mobile, b.date, b.balance
FROM account AS a
INNER JOIN (
SELECT c.date, c.cid, c.balance FROM balance AS c
INNER JOIN (
SELECT cid AS cid2, MAX(date) AS date2
FROM balance
GROUP BY cid2) AS d
ON c.cid=d.cid2
AND c.date=d.date2
) AS b
ON a.cid=b.cid
GROUP BY cid;--
答案 2 :(得分:-1)
以下陈述应该为您提供所需的结果:
SELECT cid, name, mobile, MAX(date), blance
FROM account
LEFT JOIN balance
ON account.cid = balance.cid
GROUP BY balance.cid