Question

我必须使用mysql表并尝试显示table1的结果，但是按table2排序。对于table2，我计算所有重复id的出现次数，然后显示该结果降序。以下是我可以得到的，并想知道这是否可以完成单个查询。

$query = "
SELECT DISTINCT   registration.* 

FROM              registration 

INNER JOIN        downloads 
ON                registration.id = downloads.id 

GROUP BY          downloads.COUNT(id) 
ORDER BY          downloads.COUNT(id) DESC,
                  downloads.COUNT(id) DESC

“;

Answer 1

我认为你想要这些东西：

SELECT Registration.id, Registration.name, Registration.email,
       Downloads.document
FROM Registration
JOIN Downloads
  ON Downloads.id = Registration.id
JOIN (SELECT id, COUNT(*) as count
      FROM Downloads
      GROUP BY id) Download_Count
  ON Download_Count.id = Registration.id
ORDER BY Download_Count.count DESC

（未经测试，因为OP在问题中提供样本数据和表格布局会很好）

按不同表中的数据排序mysql表

1 个答案: