Question

我想创建一个查询，如果2个字段中存在某些内容，将检查特定的类（我希望显示每个字段的含义，而不是AND）这就是我所做的，但它不起作用（基于我看到的一些例子）

    PFQuery *query = [PFQuery queryWithClassName: self.parseClassName];
   [query whereKeyExists:@"name"];  //this is based on whatever query you are trying to accomplish
    [query whereKeyExists:@"city"]; //this is based on whatever query you are trying to accomplish
    [query whereKey:@"description" containsString:searchTerm];

我应该怎么做？

**我想在我的查询中获取包含所有字段（名称，城市，描述）中的searchTeam的所有结果

由于

Answer 1

这个问题的答案很简单，只需要将多个whereKey方法调用添加到同一个查询对象中。例如：

   PFQuery *query = [PFQuery queryWithClassName: self.parseClassName];
   [query whereKey:@"name" equal:@"someName"];
   [query whereKey:@"city" equal:@"someCity"];
   [query whereKey:@"description" containsString:searchTerm];

这将评估为原始的期望陈述。

Answer 2

如果我理解你的问题，你想检查你的searchTerm是否在名称，城市或描述中。这样做的方法是：

PFQuery * nameQuery = [PFQuery queryWithClassName: self.parseClassName];
[nameQuery whereKey:"name" containsString:searchTerm];
PFQuery * cityQuery = [PFQuery queryWithClassName: self.parseClassName];
[nameQuery whereKey:"city" containsString:searchTerm];
PFQuery * descriptionQuery = [PFQuery queryWithClassName: self.parseClassName];
[nameQuery whereKey:"description" containsString:searchTerm];

PFQuery * query = [PFQuery orQueryWithSubqueries:@[nameQuery, cityQuery, descriptionQuery]];

这将从查询数组中创建复合或查询。通过向同一查询添加更多约束，您之前所做的与编写AND查询相同。

IE：keyExists：@“name”AND keyExists：@“city”AND description CONTAINS searchTerm

Answer 3

你想要这个：

NSString *className = @"YourParseClassName";
NSString *searchTerm = @"YourSearchTerm";
PFQuery *nameQuery = [PFQuery queryWithClassName:className];
[nameQuery whereKey:@"name" containsString:searchTerm];
PFQuery *cityQuery = [PFQuery queryWithClassName:className];
[cityQuery whereKey:@"city" containsString:searchTerm];
PFQuery *descriptionQuery = [PFQuery queryWithClassName:className];
[descriptionQuery whereKey:@"description" containsString:searchTerm];

PFQuery *allQuery = [PFQuery orQueryWithSubqueries:@[nameQuery, cityQuery, descriptionQuery]];
[allQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
    if (!error) {
        NSLog(@"Found objects: %@", objects);
    } else {
        NSLog(@"Received error: %@", error);
    }
}];

这样，您可以创建三个单独的查询，然后将它们组合成一个更大的查询，以便一次返回所有对象。

但请记住，Parse Regex搜索非常有限，如果您想要进行大量搜索，这可能不是最具扩展性的选项。对于轻量级工作或偶尔搜索的应用程序，这应该没问题。

使用Parse查询

3 个答案: